前置“http://"到不包含“http://"的 URL; [英] Prepending "http://" to a URL that doesn't already contain "http://"

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问题描述

我有一个保存 URL 的 input 字段,我希望这个保存的输入能够识别变量开头何时不存在Http//"但不知道从哪里开始...是否可以只检查字符串的一部分?- 然后有一个函数可以在必要时追加?

解决方案

您想要的简单解决方案如下:

var prefix = 'http://';if (s.substr(0, prefix.length) !== prefix){s = 前缀 + s;}

但是,您应该注意一些事项...

这里的测试区分大小写.这意味着如果字符串最初是 Http://example.com 这会将其更改为 http://Http://example.com 这可能不是什么你要.您可能也不应该修改任何以 foo:// 开头的字符串,否则最终可能会得到类似 http://https://example.com 的内容.>

另一方面,如果您收到诸如 example.com?redirect=http://othersite.com 之类的输入,那么您可能确实希望在 http:// 所以仅仅搜索 :// 对于通用解决方案来说可能不够好.

替代方法

  • 使用正则表达式:

    if (!s.match(/^[a-zA-Z]+:///)){s = 'http://' + s;}

  • 使用 URI 解析库,例如 JS-URI.

    if (new URI(s).scheme === null){s = 'http://' + s;}

相关问题

I have an input field that saves a URL, I'd like this saved input to recognize when "Http//" is absent from the start of the variable but have no idea where to begin... is it possible to check only a portion of a string? - then have a function that will append if necessary?

解决方案

A simple solution for what you want is the following:

var prefix = 'http://';
if (s.substr(0, prefix.length) !== prefix)
{
    s = prefix + s;
}

However there are a few things you should be aware of...

The test here is case-sensitive. This means that if the string is initially Http://example.com this will change it to http://Http://example.com which is probably not what you want. You probably should also not modify any string starting with foo:// otherwise you could end up with something like http://https://example.com.

On the other hand if you receive an input such as example.com?redirect=http://othersite.com then you probably do want to prepend http:// so just searching for :// might not be good enough for a general solution.

Alternative approaches

  • Using a regular expression:

    if (!s.match(/^[a-zA-Z]+:///))
    {
        s = 'http://' + s;
    }
    

  • Using a URI parsing library such as JS-URI.

    if (new URI(s).scheme === null)
    {
        s = 'http://' + s;
    }
    

Related questions

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