Flask-Login 引发 TypeError: 'bool' 对象在尝试覆盖 is_active 属性时不可调用 [英] Flask-Login raises TypeError: 'bool' object is not callable when trying to override is_active property

问题描述

我想修改 Flask-Login 中的 is_active 以便用户不总是处于活动状态.

I want to modify is_active in Flask-Login so that users are not always active.

默认总是返回 True，但我将其更改为返回 banned 列的值.

The default always returns True, but I changed it to return the value of the banned column.

根据文档，is_active 应该是一个属性.但是，内部 Flask-Login 代码引发了:

Based on the docs, is_active should be a property. However, the internal Flask-Login code raises:

TypeError: 'bool' object is not callable 

尝试使用 is_active 时.

如何正确使用 is_active 停用某些用户?

How do I correctly use is_active to deactivate some users?

class User(UserMixin, db.Model):
    id = db.Column(db.Integer, primary_key=True)
    banned = db.Column(db.Boolean, default=False)

    @property
    def is_active(self):
        return self.banned

<小时>

login_user(user, form.remember_me.data)

if not force and not user.is_active():
TypeError: 'bool' object is not callable

推荐答案

is_active、is_anonymous 和 is_authenticated 都是 Flask 的属性- 登录 0.3.如果要使用它们，请将它们视为属性，不要调用它们.如果你想覆盖它们，记得用 @property 装饰它们.

is_active, is_anonymous, and is_authenticated are all properties as of Flask-Login 0.3. If you want to use them, treat them as attributes, don't call them. If you want to override them, remember to decorate them with @property.

# change from
current_user.is_authenticated()
# to
current_user.is_authenticated

看来您正在阅读最新版本 (0.3) 的文档，但使用的是旧版本的库.0.3 版 包含一项重大更改，将这些属性从方法更改为属性.您应该升级到最新版本的 Flask-Login 并将它们视为属性.

It appears you are reading the docs for the most recent version (0.3), but using an older version of the library. Version 0.3 contains a breaking change which changed these attributes from methods to properties. You should upgrade to the latest version of Flask-Login and treat them as properties.

通过使用户的 is_active 属性返回 False 来停用用户.您返回列值的想法很好.

You deactivate the user by causing its is_active property to return False. Your idea to return the value of a column is fine.

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