如何链接ajax请求? [英] How to chain ajax requests?

问题描述

我必须与迫使我链接请求的远程 API 进行交互.这是异步模式下的回调地狱:

I have to interact with a remote api that forces me to chain requests. Thats a callback-hell in asynchronous mode:

// pseudocode: ajax(request_object, callback)
ajax(a, function() {
  ajax(b(a.somedata), function() {
    ajax(c(b.somedata), function() {
      c.finish()
    }
  }) 
})

在同步模式下可读性更高:

It would be much more readable in sync mode:

sjax(a)
sjax(b(a.somedata))
sjax(c(b.somedata))
c.finish()

但是 Sjax 是邪恶的 :) 我如何以 nice 不那么邪恶和可读的方式做到这一点?

But Sjax is evil :) How do I do that in a nice not-so-evil and readable way?

推荐答案

不要使用匿名函数.给他们起名字.我不知道你是否能够做到我在下面写的:

Don't use anonymous functions. Give them names. I don't know if you're able to do what I wrote below though:

var step_3 = function() {
    c.finish();
};

var step_2 = function(c, b) {
    ajax(c(b.somedata), step_3);
};

var step_1 = function(b, a) {
  ajax(b(a.somedata), step_2);
};

ajax(a, step_1);

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