bash:静默杀死后台函数进程 [英] bash: silently kill background function process

问题描述

贝壳大师，

我有一个 bash shell 脚本，我在其中启动了一个后台函数，比如 foo()，以显示一个无聊而冗长的命令的进度条:

I have a bash shell script, in which I launch a background function, say foo(), to display a progress bar for a boring and long command:

foo()
{
    while [ 1 ]
    do
        #massively cool progress bar display code
        sleep 1
    done
}

foo &
foo_pid=$!

boring_and_long_command
kill $foo_pid >/dev/null 2>&1
sleep 10

现在，当 foo 死亡时，我看到以下文本:

now, when foo dies, I see the following text:

/home/user/script: line XXX: 30290 Killed                  foo

这完全破坏了我的非常酷的进度条显示.

This totally destroys the awesomeness of my, otherwise massively cool, progress bar display.

我如何摆脱这条消息?

推荐答案

kill $foo_pid
wait $foo_pid 2>/dev/null

顺便说一句，我不知道你的非常酷的进度条，但是你见过 Pipe Viewer (pv) 吗?http://www.ivarch.com/programs/pv.shtml

BTW, I don't know about your massively cool progress bar, but have you seen Pipe Viewer (pv)? http://www.ivarch.com/programs/pv.shtml

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