在 C# 中,如何在方法中实例化传递的泛型类型? [英] In C#, how to instantiate a passed generic type inside a method?

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问题描述

如何在下面的 InstantiateType 方法中实例化类型 T?

How can I instantiate the type T inside my InstantiateType<T> method below?

我收到错误消息:T"是类型参数",但用作变量".:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace TestGeneric33
{
    class Program
    {
        static void Main(string[] args)
        {
            Container container = new Container();
            Console.WriteLine(container.InstantiateType<Customer>("Jim", "Smith"));
            Console.WriteLine(container.InstantiateType<Employee>("Joe", "Thompson"));
            Console.ReadLine();
        }
    }

    public class Container
    {
        public T InstantiateType<T>(string firstName, string lastName) where T : IPerson
        {
            T obj = T();
            obj.FirstName(firstName);
            obj.LastName(lastName);
            return obj;
        }

    }

    public interface IPerson
    {
        string FirstName { get; set; }
        string LastName { get; set; }
    }

    public class Customer : IPerson
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public string Company { get; set; }
    }

    public class Employee : IPerson
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public int EmployeeNumber { get; set; }
    }
}

重构答案:

感谢所有评论,他们让我走上了正轨,这就是我想做的:

REFACTORED ANSWER:

Thanks for all the comments, they got me on the right track, this is what I wanted to do:

using System;

namespace TestGeneric33
{
    class Program
    {
        static void Main(string[] args)
        {
            Container container = new Container();
            Customer customer1 = container.InstantiateType<Customer>("Jim", "Smith");
            Employee employee1 = container.InstantiateType<Employee>("Joe", "Thompson");
            Console.WriteLine(PersonDisplayer.SimpleDisplay(customer1));
            Console.WriteLine(PersonDisplayer.SimpleDisplay(employee1));
            Console.ReadLine();
        }
    }

    public class Container
    {
        public T InstantiateType<T>(string firstName, string lastName) where T : IPerson, new()
        {
            T obj = new T();
            obj.FirstName = firstName;
            obj.LastName = lastName;
            return obj;
        }
    }

    public interface IPerson
    {
        string FirstName { get; set; }
        string LastName { get; set; }
    }

    public class PersonDisplayer
    {
        private IPerson _person;

        public PersonDisplayer(IPerson person)
        {
            _person = person;
        }

        public string SimpleDisplay()
        {
            return String.Format("{1}, {0}", _person.FirstName, _person.LastName);
        }

        public static string SimpleDisplay(IPerson person)
        {
            PersonDisplayer personDisplayer = new PersonDisplayer(person);
            return personDisplayer.SimpleDisplay();
        }
    }

    public class Customer : IPerson
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public string Company { get; set; }
    }

    public class Employee : IPerson
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public int EmployeeNumber { get; set; }
    }
}

推荐答案

像这样声明你的方法:

public string InstantiateType<T>(string firstName, string lastName) 
              where T : IPerson, new()

注意最后的附加约束.然后在方法体中创建一个 new 实例:

Notice the additional constraint at the end. Then create a new instance in the method body:

T obj = new T();    

这篇关于在 C# 中,如何在方法中实例化传递的泛型类型?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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