片段中的 getLayoutInflater() [英] getLayoutInflater() in fragment

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本文介绍了片段中的 getLayoutInflater()的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我试图在 Fragment 上的 ListView 中显示我的搜索结果,但它失败了:

LayoutInflater inflater = getLayoutInflater();

<块引用>

Fragment 类型中的 getLayoutInflater(Bundle) 方法不是适用于参数 ()

这是我的代码:

public View getView(int position, View convertView, ViewGroup parent){LayoutInflater inflater = getLayoutInflater();查看行;row = inflater.inflate(R.layout.list_single, parent, false);TextView textview = (TextView) row.findViewById(R.id.TextView01);ImageView imageview = (ImageView) 行.findViewById(R.id.ImageView01);textview.setText(data_text[位置]);imageview.setImageResource(data_image[位置]);返回(行);}

我该如何解决这个问题?

解决方案

如果你在想要的片段

getActivity().getLayoutInflater();

LayoutInflater.from(getActivity());

你也可以

View.inflate();

LayoutInflater inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

I'm trying to show my results search in a ListView on the Fragment, but it fails on:

LayoutInflater inflater = getLayoutInflater();

The method getLayoutInflater(Bundle) in the type Fragment is not applicable for the arguments ()

This is my code:

public View getView(int position, View convertView, ViewGroup parent)
  {
   LayoutInflater inflater = getLayoutInflater();
   View row;

   row = inflater.inflate(R.layout.list_single, parent, false);

   TextView textview = (TextView) row.findViewById(R.id.TextView01);
   ImageView imageview = (ImageView) row
     .findViewById(R.id.ImageView01);

   textview.setText(data_text[position]);
   imageview.setImageResource(data_image[position]);

   return (row);

  }

How can I fix this?

解决方案

if you are in a fragment you want

getActivity().getLayoutInflater();

or

LayoutInflater.from(getActivity());

also you can do

View.inflate();

or

LayoutInflater inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

这篇关于片段中的 getLayoutInflater()的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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