过滤 S3 列表对象结果以找到匹配模式的键 [英] Filter S3 list-objects results to find a key matching a pattern

问题描述

我想使用 AWS CLI 查询存储桶的内容并查看特定文件是否存在，但该存储桶包含数千个文件.如何过滤结果以仅显示与模式匹配的键名?例如:

I would like to use the AWS CLI to query the contents of a bucket and see if a particular file exists, but the bucket contains thousands of files. How can I filter the results to only show key names that match a pattern? For example:

aws s3api list-objects --bucket myBucketName --query "Contents[?Key==*mySearchPattern*]"

推荐答案

--query 参数使用 JMESPath 表达式.JMESPath 有一个内部函数 contains 允许您搜索字符串模式.

The --query argument uses JMESPath expressions. JMESPath has an internal function contains that allows you to search for a string pattern.

这应该会得到想要的结果:

This should give the desired results:

aws s3api list-objects --bucket myBucketName --query "Contents[?contains(Key, `mySearchPattern`)]"

(对于 Linux，我需要在 mySearchPattern 周围使用单引号 ' 而不是反引号 `.)

(With Linux I needed to use single quotes ' rather than back ticks ` around mySearchPattern.)

如果您想搜索以某些字符开头的键 ，您还可以使用 --prefix 参数:

If you want to search for keys starting with certain characters, you can also use the --prefix argument:

aws s3api list-objects --bucket myBucketName --prefix "myPrefixToSearchFor"

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