通过嵌套json递归迭代python中的特定键 [英] recursive iteration through nested json for specific key in python

问题描述

我正在尝试从 json 文件中提取嵌套值.我想打印出每个id"键的每个值.我想我很接近但无法弄清楚为什么 obj 类型从 dict 更改为列表，然后为什么我无法解析该列表.这是我正在使用的 json 的链接:http://hastebin.com/ratevimixa.tex

I'm trying to pull nested values from a json file. I want to print out each of the values for every "id" key. I think I'm close but can't figure out why the obj type changes from a dict to a list, and then why I'm unable to parse that list. Here is a link to the json I'm working with: http://hastebin.com/ratevimixa.tex

这是我当前的代码:

#!/usr/bin/env python
#-*- coding: utf-8 -*-

import json

json_data = open('JubJubProductions.json', 'r+')
jdata = json.loads(json_data.read().decode("utf-8"))

def recursion(dict):

    for key, value in dict.items():

        if type(value) == type(dict):
            if key != "paging":
                for key, value in value.items():
                    if isinstance (value,list):
                        print key
                        # place where I need to enter list comprehension?
                if type(value) == type(dict):
                    if key == "id":
                        print " id found " + value
                    if key != "id":
                        print key + " 1st level"
                if key == "id":
                    print key
        else:
            if key == "id":
                print "id found " + value       
if __name__ == '__main__':
    recursion(jdata)

--------------------------------------------------------------------------------------------更新

这就是我现在正在使用的，它将返回一个 id 值，但不是全部:

-------------------------------------------------------------------------------------------update

This is now what I'm working with and it'll return a single id value, but not all of them:

#!/usr/bin/env python
#-*- coding: utf-8 -*-

import json

json_data = open('jubjubProductions', 'r+')
jdata = json.loads(json_data.read().decode("utf-8"))

def id_generator(d):
    for k, v in d.items():
        if k == "id":
            yield v
        elif isinstance(v, dict):
            for id_val in id_generator(v):
                yield id_val

if __name__ == '__main__':
    for _ in id_generator(jdata):
        print (_)

推荐答案

def id_generator(dict_var):
    for k, v in dict_var.items():
        if k == "id":
            yield v
        elif isinstance(v, dict):
            for id_val in id_generator(v):
                yield id_val

这将创建一个迭代器，它将产生键id"下任何级别的每个值.示例用法(打印所有这些值):

This will create an iterator which will yield every value on any level under key "id". Example usage (printing all of those values):

for _ in id_generator(some_json_dict):
    print(_)

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