Php递归获取字符串的所有可能性 [英] Php recursion to get all possibilities of strings
问题描述
这是我获得所有可能性的代码:
Here is my code to get all possibilities:
$seq[1] = 'd';
$seq[2] = 'f';
$seq[3] = 'w';
$seq[4] = 's';
for($i = 1; $i < 5; $i++)
{
$s['length_1'][] = $seq[$i];
$c1++;
for($i2 = $i+1; $i2 < 5; $i2++)
{
$s['length_2'][] = $seq[$i].$seq[$i2];
$last = $seq[$i].$seq[$i2];
$c2++;
for($i3 = $i2+1; $i3 < 5; $i3++)
{
$s['length_3'][] = $last.$seq[$i3];
$last = $last.$seq[$i3];
$c3++;
for($i4 = $i3+1; $i4 < 5; $i4++)
{
$s['length_4'][] = $last.$seq[$i4];
$c4++;
}
}
}
}
for($i = 0; $i < $c1; $i++)
echo $s['length_1'][$i].'<br>';
for($i = 0; $i < $c2; $i++)
echo $s['length_2'][$i].'<br>';
for($i = 0; $i < $c3; $i++)
echo $s['length_3'][$i].'<br>';
for($i = 0; $i < $c4; $i++)
echo $s['length_4'][$i].'<br>';
但是如果我想添加更多,那么我将不得不再添加一个循环.那么,我怎样才能用递归来做到这一点呢?我尝试,我尝试,但我真的做不到.请帮助并尽可能简单地发布示例.
But if I want to add more, then I will have to add one more loop. So, how can I do it with recursion? I try, I try, but I really can't do it. Please help and post example as simple as possible.
谢谢.
推荐答案
这是一个简单的算法.从 1 迭代到 2count(array)-1.在每次迭代中,如果循环计数器的二进制表示中的第 j 位等于 1,则在组合中包含第 j 个元素.
Here's a simple algo. Iterate from 1 to 2count(array)-1. On each iteration, if j-th bit in a binary representation of the loop counter is equal to 1, include j-th element in a combination.
由于 PHP 需要能够将 2count(array) 计算为整数,因此这可能永远不会超过 PHP_INT_MAX
.在 64 位 PHP 安装中,您的数组不能超过 62 个元素,因为 262 低于 PHP_INT_MAX
而 263 超过它.
As PHP needs to be able to calculate 2count(array) as an integer, this may never exceed PHP_INT_MAX
. On a 64-bit PHP installation your array cannot have more than 62 elements, as 262 stays below PHP_INT_MAX
while 263 exceeds it.
这会计算所有可能的组合,而不是排列(即,'abc' = 'cba').它通过以二进制表示原始数组并从 0 到整个数组的二进制表示向上计数",从而有效地构建每个可能的唯一组合的列表.
This computes all possible combinations, not permutations (ie, 'abc' = 'cba'). It does so by representing the original array in binary and "counting up" from 0 to the binary representation of the full array, effectively building a list of every possible unique combination.
$a = array('a', 'b', 'c', 'd');
$len = count($a);
$list = array();
for($i = 1; $i < (1 << $len); $i++) {
$c = '';
for($j = 0; $j < $len; $j++)
if($i & (1 << $j))
$c .= $a[$j];
$list[] = $c;
}
print_r($list);
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