如何在 Javascript 中解析 URL 查询参数? [英] How do I parse a URL query parameters, in Javascript?

问题描述

可能的重复:
在javascript中使用url的get参数
如何在 JavaScript 中获取查询字符串值?

在 Javascript 中，如何获取 URL 字符串的参数(不是当前 URL)?

In Javascript, how can I get the parameters of a URL string (not the current URL)?

喜欢:

www.domain.com/?v=123&p=hello

我可以在 JSON 对象中获取v"和p"吗?

Can I get "v" and "p" in a JSON object?

推荐答案

今天(这个答案 2.5 年后)你可以 安全使用 Array.forEach.正如@ricosrealm 所建议的，在这个函数中使用了 decodeURIComponent.

Today (2.5 years after this answer) you can safely use Array.forEach. As @ricosrealm suggests, decodeURIComponent was used in this function.

function getJsonFromUrl(url) {
  if(!url) url = location.search;
  var query = url.substr(1);
  var result = {};
  query.split("&").forEach(function(part) {
    var item = part.split("=");
    result[item[0]] = decodeURIComponent(item[1]);
  });
  return result;
}

其实没那么简单，看评论里的同行评议，特别是:

actually it's not that simple, see the peer-review in the comments, especially:

• 基于哈希的路由 (@cmfolio)
• 数组参数 (@user2368055)
• 正确使用 decodeURIComponent 和未编码的 = (@AndrewF)
• 非编码+(由我添加)

• hash based routing (@cmfolio)
• array parameters (@user2368055)
• proper use of decodeURIComponent and non-encoded = (@AndrewF)
• non-encoded + (added by me)

有关更多详细信息，请参阅 MDN 文章 和 RFC 3986.

For further details, see MDN article and RFC 3986.

也许这应该转到 codereview SE，但这里是更安全且无正则表达式的代码:

Maybe this should go to codereview SE, but here is safer and regexp-free code:

function getJsonFromUrl(url) {
  if(!url) url = location.href;
  var question = url.indexOf("?");
  var hash = url.indexOf("#");
  if(hash==-1 && question==-1) return {};
  if(hash==-1) hash = url.length;
  var query = question==-1 || hash==question+1 ? url.substring(hash) : 
  url.substring(question+1,hash);
  var result = {};
  query.split("&").forEach(function(part) {
    if(!part) return;
    part = part.split("+").join(" "); // replace every + with space, regexp-free version
    var eq = part.indexOf("=");
    var key = eq>-1 ? part.substr(0,eq) : part;
    var val = eq>-1 ? decodeURIComponent(part.substr(eq+1)) : "";
    var from = key.indexOf("[");
    if(from==-1) result[decodeURIComponent(key)] = val;
    else {
      var to = key.indexOf("]",from);
      var index = decodeURIComponent(key.substring(from+1,to));
      key = decodeURIComponent(key.substring(0,from));
      if(!result[key]) result[key] = [];
      if(!index) result[key].push(val);
      else result[key][index] = val;
    }
  });
  return result;
}

这个函数甚至可以解析像

This function can parse even URLs like

var url = "?foo%20e[]=a%20a&foo+e[%5Bx%5D]=b&foo e[]=c";
// {"foo e": ["a a",  "c",  "[x]":"b"]}

var obj = getJsonFromUrl(url)["foo e"];
for(var key in obj) { // Array.forEach would skip string keys here
  console.log(key,":",obj[key]);
}
/*
  0 : a a
  1 : c
  [x] : b
*/

这篇关于如何在 Javascript 中解析 URL 查询参数?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！