传递带括号的 URL 以卷曲 [英] Passing a URL with brackets to curl

问题描述

如果我尝试将包含括号的 URL 传递给 curl，它会失败并显示错误:

If I try to pass a URL to curl that contains brackets, it fails with an error:

$ curl 'http://www.google.com/?TEST[]=1'
curl: (3) [globbing] illegal character in range specification at pos 29

但是，如果我转义两个括号，它似乎工作:

However, if I escape both brackets, it appears to work:

$ curl 'http://www.google.com/?TEST[]=1'

有趣的是，我使用反斜杠来转义仅第一个括号它以错误代码 20497 静默失败:

Interestingly, I use a backslash to escape only the first bracket it fails silently with error code 20497:

$ curl 'http://www.google.com/?TEST[]=1'
$ echo $!
20497

我的问题是如何在一般情况下解决这个问题?是否有一个参数会自动转义 URL，或者在传递给 curl 之前需要转义的字符的描述?

My question is how to fix this for general cases? Is there an argument that will escape URLs automatically, or a description of the characters that need to be escaped before passing to curl?

推荐答案

没关系，我在文档中找到了:

Never mind, I found it in the docs:

-g/--globoff
              This  option  switches  off  the "URL globbing parser". When you set this option, you can
              specify URLs that contain the letters {}[] without having them being interpreted by  curl
              itself.  Note  that  these  letters  are not normal legal URL contents but they should be
              encoded according to the URI standard.

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