Java:从 FilePath 获取 URI [英] Java: Get URI from FilePath

问题描述

我对Java知之甚少.我需要从 Windows 上的 FilePath(String) 构造一个 URI 的字符串表示.有时我得到的 inputFilePath 是:file:/C:/a.txt 有时是:C:/a.txt.现在，我正在做的是:

I've little knowledge of Java. I need to construct a string representation of an URI from FilePath(String) on windows. Sometimes the inputFilePath I get is: file:/C:/a.txt and sometimes it is: C:/a.txt. Right now, what I'm doing is:

new File(inputFilePath).toURI().toURL().toExternalForm()

以上适用于不以 file:/ 为前缀的路径，但对于以 file:/ 为前缀的路径，.toURI 方法通过附加当前目录的值将其转换为无效的 URI，因此路径变得无效.

The above works fine for paths, which are not prefixed with file:/, but for paths prefixed with file:/, the .toURI method is converting it to a invalid URI, by appending value of current dir, and hence the path becomes invalid.

请帮我建议一个正确的方法来为这两种路径获取正确的 URI.

Please help me out by suggesting a correct way to get the proper URI for both kind of paths.

推荐答案

这些是有效的文件 uri:

These are the valid file uri:

file:/C:/a.txt            <- On Windows
file:///C:/a.txt          <- On Windows
file:///home/user/a.txt   <- On Linux

因此您需要删除 file:/ 或 file:///(对于 Windows)和 file://(对于 Linux).

So you will need to remove file:/ or file:/// for Windows and file:// for Linux.

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