网页抓取 Instagram 粉丝数 BeautifulSoup [英] Webscraping Instagram follower count BeautifulSoup

问题描述

我刚刚开始学习如何使用 BeautifulSoup 进行网页抓取，并想编写一个简单的程序来获取给定 Instagram 页面的关注者数量.我目前有以下脚本(从另一个问答线程中提取):

I'm just starting to learn how to web scrape using BeautifulSoup and want to write a simple program that will get the follower count for a given Instagram page. I currently have the following script (pulled from another Q&A thread):

import requests
from bs4 import BeautifulSoup

user = "espn"
url = 'https://www.instagram.com/'+ user
r = requests.get(url)
soup = BeautifulSoup(r.content)
followers = soup.find('meta', {'name': 'description'})['content']
follower_count = followers.split('Followers')[0]
print(follower_count)

# 10.7m

我遇到的问题是我想获得一个更精确的数字，当您将鼠标悬停在 Instagram 页面上的关注者计数上时，您可以看到该数字(例如，10,770,816).

The problem I am running into is I want to get a more precise number, which you can see when you hover the mouse over the follower count on the Instagram page (e.g., 10,770,816).

不幸的是，我一直无法弄清楚如何使用 BeautifulSoup 做到这一点.我想在没有 API 的情况下执行此操作，因为我将其与代码相结合以跟踪其他社交媒体平台.有什么提示吗?

Unfortunately, I have not been able to figure out how to do this with BeautifulSoup. I'd like to do this without the API since I am combining this with code to track other social media platforms. Any tips?

推荐答案

使用 API 是最简单的方法，但我也发现了一个非常hacky 的方法:

Use the API is the easiest way, but I also found a very hacky way to do it:

import requests

username = "espn"
url = 'https://www.instagram.com/' + username
r = requests.get(url).text

start = '"edge_followed_by":{"count":'
end = '},"followed_by_viewer"'
followers= r[r.find(start)+len(start):r.rfind(end)]

start = '"edge_follow":{"count":'
end = '},"follows_viewer"'
following= r[r.find(start)+len(start):r.rfind(end)]

print(followers, following)

如果你查看响应请求给出的，有一行包含真实粉丝数的 Javascript:

If you look through the response requests gives, theres a line of Javascript that contains the real follower count:

...edge_followed_by":{"count":10770969},"followed_by_viewer":{...

所以我只是通过查找前后的子字符串来提取数字.

So I just extracted the number by finding the substring before and after.

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