如何在不实例化的情况下检查一个类是否继承了另一个类? [英] How to check if a class inherits another class without instantiating it?

问题描述

假设我有一个看起来像这样的类:

Suppose I have a class that looks like this:

class Derived : // some inheritance stuff here
{
}

我想在我的代码中检查类似的东西:

I want to check something like this in my code:

Derived is SomeType;

但是看起来 is 运算符需要 Derived 是 Dervied 类型的变量，而不是 Derived 本身.我不想创建派生类型的对象.
如何确保 Derived 继承 SomeType 而不实例化它?

But looks like is operator need Derived to be variable of type Dervied, not Derived itself. I don't want to create an object of type Derived.
How can I make sure Derived inherits SomeType without instantiating it?

P.S. 如果有帮助，我想要一些类似于 where 关键字对泛型的作用.

类似于 this 答案，但它正在检查一个对象.我想检查课程本身.

P.S. If it helps, I want something like what where keyword does with generics.

Similar to this answer, but it's checking an object. I want to check the class itself.

推荐答案

要检查可分配性，您可以使用 Type.IsAssignableFrom 方法:

To check for assignability, you can use the Type.IsAssignableFrom method:

typeof(SomeType).IsAssignableFrom(typeof(Derived))

这将如您对类型相等、继承关系和接口实现所期望的那样工作，但不是当您在寻找跨显式/隐式转换运算符的可赋值性"时.

This will work as you expect for type-equality, inheritance-relationships and interface-implementations but not when you are looking for 'assignability' across explicit / implicit conversion operators.

要检查严格继承，您可以使用Type.IsSubclassOf:

To check for strict inheritance, you can use Type.IsSubclassOf:

typeof(Derived).IsSubclassOf(typeof(SomeType))

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