类中的 java 构造函数不能应用于给定类型 [英] java constructor in class cannot be applied to given types
问题描述
我有 2 个子类:职员、学生它们属于超类 Person.
I have 2 subclasses: Staff, Student they belong to superclass Person.
这是我老师给的代码(任务):
Here is the code(tasks) which is given by my teacher:
public class Person
{
private String name;
private int yearOfBirth;
/**
* Create a person with given name and age.
*/
Person(String name, int yearOfBirth)
{
this.name = name;
this.yearOfBirth = yearOfBirth;
}
}
<小时>
class Student extends Person
{
private String SID; // student ID number
/**
* Create a student with no parameters.
*/
Student()
{
//task.
}
}
<小时>
public class Staff extends Person
{
private String roomNumber;
/**
* Construct a staff member with field values and no pamaeters.
*/
public Staff()
{
//task
}
}
我不知道我可以输入什么来创建一个没有参数的对象.它总是出现这样的错误:类 Person 中的构造函数 Person 不能应用于给定类型;必需:java.lang.String,int;
I don't know what can I type in order to create an object without parameter. It always appears an error like: constructor Person in class Person cannot be applied to given types; required: java.lang.String,int;
我在网上查过有两种方法可以解决这个问题:
I have checked online that there are 2 ways to solve the problem:
在超类中添加一个默认值:
Person()//没有参数
.
在子类 Student 中:
In the subclass Student:
Student()
{
Person astudent = new Student() //I guess.
}
- 在子类中添加一个 super():
Student()
{
super("xxx")//I guess.
}
我不知道该怎么办.我是学习 BlueJ 的初学者.希望任何人都可以帮助我.非常感谢.
I don't know what to do. I an a starter in learning BlueJ. Hope anyone can help me. Thank you very much.
推荐答案
由于您的超类 Person
没有默认构造函数,因此在您的子类 (Student
和 Staff
),则必须调用超类构造函数作为第一条语句.
Since your super class Person
doesn't have a default constructor, in your sub classes (Student
and Staff
), you must call the super class constructor as the first statement.
你应该像这样定义你的子类构造函数:
You should define your sub class constructors like this:
Student() {
super("a_string_value", an_int_value);// You have to pass String and int values to super class
}
<小时>
Staff() {
super("a_string_value", an_int_value); // You have to pass String and int values to super class
}
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