用 PHP 连接两个 MySQL 表 [英] Join two MySQL tables with PHP
问题描述
例如,我创建了两个页面和两个 MySQL 表.
For example, I have created two pages and two MySQL tables.
Index.php
&citys.php
城市
ID City Country Population
--------------------------------------
1 Amsterdam NL 1500000
2 Rotterdam NL 900000
3 Dusseldorf DE 1800000
评论
ID City Name Comment
---------------------------------
1 Dusseldorf Jack Great city!
2 Dusseldorf John Beautiful
3 Rotterdam Emy Love it
目前我只像这样使用citys
表:
At the moment I only use the table citys
like this:
index.php
链接到 citys.php
:
<a href='citys.php?cmd=menu&id=";echo $row['id'];echo "'>
和 citys.php
使用此代码显示来自 MySQL 的数据:
And citys.php
use this code to show the data from MySQL:
<?php
include "connect.php";
if(!isset($cmd))
{
if($_GET["cmd"]=="menu" || $_POST["cmd"]=="menu")
{
if (!isset($_POST["submit"]))
{
$id = $_GET["id"];
$sql = "SELECT * FROM citys WHERE id=$id";
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
?>
<?php echo $row["City"] ?>
<br><br>
<?php echo $row["Country"] ?>
<br><br>
<?php echo $row["Population"] ?>
直到这里一切都显示出来并且工作正常.
Until here everything is showing up and working fine.
但我也想显示第 2 页上的评论.因此必须编辑查询才能从表 comments
中获取正确的数据.
But I also want to show the comments on page 2. So the query has to be edited to also get the right data from the table comments
.
我尝试了来自互联网的不同示例,这些示例是我自己编辑的:
I tried different examples from internet that I have edited myself like:
<?php
include "connect.php";
if(!isset($cmd))
{
if($_GET["cmd"]=="menu" || $_POST["cmd"]=="menu")
{
if (!isset($_POST["submit"]))
{
$id = $_GET["id"];
$sql = "SELECT citys.*, comments.* FROM citys, comments WHERE citys.id=$id AND comments.city=citys.city";
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
?>
但没有任何效果.
我该如何解决这个问题?
How can I fix this?
来自 VIPIN JAIN 的回答的查询有效,但还有一个问题:
The query from VIPIN JAIN's answer works, but there is one problem left:
查询:
$sql = "SELECT * FROM citys LEFT JOIN comments ON comments.city=citys.city WHERE citys.id=$id";
如果表 'comments' 有三行,则此代码仅显示最后两行而不显示第一行:
If the table 'comments' has three rows, this code shows only the last two but not the first:
<?php
while($row = mysql_fetch_array($result)) {
echo "<br><br>";
echo $row['name'];
echo "<br>";
echo $row['comment'];
}
?>
如果我尝试这样做,它只会显示第一行.
And if I try this it only shows the first row.
<?php echo $row["name"] ?>
<br>
<?php echo $row["comment"] ?>
我不知道为什么第一条记录留在循环中.
I don't know why the first record is left away in the loop.
推荐答案
使用此查询
$sql = "SELECT * FROM citys LEFT JOIN comments ON comments.city=citys.city WHERE citys.id=$id";
将 leftjoin 用于此类工作
Use leftjoin for this type of work
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