NSString - 仅转换为纯字母(即删除重音+标点) [英] NSString - Convert to pure alphabet only (i.e. remove accents+punctuation)

问题描述

我正在尝试比较没有任何标点符号、空格、重音符号等的名称.目前我正在做以下事情:

I'm trying to compare names without any punctuation, spaces, accents etc. At the moment I am doing the following:

-(NSString*) prepareString:(NSString*)a {
    //remove any accents and punctuation;
    a=[[[NSString alloc] initWithData:[a dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES] encoding:NSASCIIStringEncoding] autorelease];

    a=[a stringByReplacingOccurrencesOfString:@" " withString:@""];
    a=[a stringByReplacingOccurrencesOfString:@"'" withString:@""];
    a=[a stringByReplacingOccurrencesOfString:@"`" withString:@""];
    a=[a stringByReplacingOccurrencesOfString:@"-" withString:@""];
    a=[a stringByReplacingOccurrencesOfString:@"_" withString:@""];
    a=[a lowercaseString];
    return a;
}

但是，我需要对数百个字符串执行此操作，并且需要使其更高效.有什么想法吗?

However, I need to do this for hundreds of strings and I need to make this more efficient. Any ideas?

推荐答案

NSString* finish = [[start componentsSeparatedByCharactersInSet:[[NSCharacterSet letterCharacterSet] invertedSet]] componentsJoinedByString:@""];

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