如何在 Django 中重定向到不同的 URL? [英] How can I redirect to a different URL in Django?

问题描述

我有两个页面，一个是显示特定项目的详细信息，另一个是搜索项目.假设 urls.py 已为它们和我的应用程序在 views.py 中正确配置，我有:

I have two pages, one which is to display details for a specific item and another to search for items. Let's say that the urls.py is properly configured for both of them and within views.py for my app, I have:

def item(request, id):
    return render(request, 'item.html', data)

def search(request):
    #use GET to get query parameters
    if len(query)==1:
        #here, I want to redirect my request to item, passing in the id
    return render(request, 'search.html', data)

我该怎么做才能正确重定向请求?我试过 return item(request, id) 并呈现正确的页面，但它不会更改地址栏中的 URL.我怎样才能让它真正重定向而不是仅仅呈现我的另一个页面?项目页面的 URL 模式是 /item/{id}.我已经查看了关于 SO 和文档的类似问题的答案，但仍然无法弄清楚.

What do I do to properly redirect the request? I've tried return item(request, id) and that renders the correct page, but it doesn't change the URL in the address bar. How can I make it actually redirect instead of just rendering my other page? The URL pattern for the item page is /item/{id}. I've looked at the answer to similar questions on SO and the documentation, but still couldn't figure it out.

我不到一周前才开始学习 Python，另一个答案不够清楚，无法帮助我.

I just started learning Python less than a week ago and the other answer isn't clear enough to help me out.

编辑 2:Nvm，不确定我之前做错了什么，但是当我再次尝试时它起作用了.

Edit 2: Nvm, not sure what I did wrong before, but it worked when I tried it again.

推荐答案

您可以使用 HttpResponseRedirect:

You can use HttpResponseRedirect:

from django.http import HttpResponseRedirect

# ...

return HttpResponseRedirect('/url/url1/')

url"在哪里和url1"等于重定向的路径.

Where "url" and "url1" equals the path to the redirect.

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