将两个 GCC 编译的 .o 目标文件合并到第三个 .o 文件中 [英] combine two GCC compiled .o object files into a third .o file

问题描述

如何将两个 GCC 编译的 .o 目标文件合并为第三个 .o 文件?

How does one combine two GCC compiled .o object files into a third .o file?

$ gcc -c  a.c -o a.o
$ gcc -c  b.c -o b.o
$ ??? a.o b.o -o c.o
$ gcc c.o other.o -o executable

如果您有权访问源文件，-combine GCC 标志将在编译前合并源文件:

If you have access to the source files the -combine GCC flag will merge the source files before compilation:

$ gcc -c -combine a.c b.c -o c.o

然而这仅适用于源文件，并且 GCC 不接受 .o 文件作为此命令的输入.

However this only works for source files, and GCC does not accept .o files as input for this command.

通常，链接 .o 文件无法正常工作，因为您不能将链接器的输出用作它的输入.结果是一个共享库，并没有静态链接到生成的可执行文件中.

Normally, linking .o files does not work properly, as you cannot use the output of the linker as input for it. The result is a shared library and is not linked statically into the resulting executable.

$ gcc -shared a.o b.o -o c.o
$ gcc c.o other.o -o executable
$ ./executable
./executable: error while loading shared libraries: c.o: cannot open shared object file: No such file or directory
$ file c.o
c.o: ELF 32-bit LSB shared object, Intel 80386, version 1 (SYSV), dynamically linked, not stripped
$ file a.o
a.o: ELF 32-bit LSB relocatable, Intel 80386, version 1 (SYSV), not stripped

推荐答案

将 -relocatable 或 -r 传递给 ld 将创建一个对象适合作为 ld 的输入.

Passing -relocatable or -r to ld will create an object that is suitable as input of ld.

$ ld -relocatable a.o b.o -o c.o
$ gcc c.o other.o -o executable
$ ./executable

生成的文件与原始.o文件的类型相同.

The generated file is of the same type as the original .o files.

$ file a.o
a.o: ELF 32-bit LSB relocatable, Intel 80386, version 1 (SYSV), not stripped
$ file c.o
c.o: ELF 32-bit LSB relocatable, Intel 80386, version 1 (SYSV), not stripped

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