漂亮的打印 2D 列表? [英] Pretty print 2D list?

问题描述

是否有一种简单的内置方法可以将 2D Python 列表打印为 2D 矩阵?

Is there a simple, built-in way to print a 2D Python list as a 2D matrix?

所以:

[["A", "B"], ["C", "D"]]

会变成这样

A    B
C    D

我找到了 pprint 模块，但它似乎没有做我想要的.

I found the pprint module, but it doesn't seem to do what I want.

推荐答案

为了让事情变得有趣，让我们尝试使用更大的矩阵:

To make things interesting, let's try with a bigger matrix:

matrix = [
   ["Ah!",  "We do have some Camembert", "sir"],
   ["It's a bit", "runny", "sir"],
   ["Well,",  "as a matter of fact it's", "very runny, sir"],
   ["I think it's runnier",  "than you",  "like it, sir"]
]

s = [[str(e) for e in row] for row in matrix]
lens = [max(map(len, col)) for col in zip(*s)]
fmt = '	'.join('{{:{}}}'.format(x) for x in lens)
table = [fmt.format(*row) for row in s]
print '
'.join(table)

输出:

Ah!                     We do have some Camembert   sir            
It's a bit              runny                       sir            
Well,                   as a matter of fact it's    very runny, sir
I think it's runnier    than you                    like it, sir  

UPD:对于多行单元格，这样的事情应该可以工作:

UPD: for multiline cells, something like this should work:

text = [
    ["Ah!",  "We do have
some Camembert", "sir"],
    ["It's a bit", "runny", "sir"],
    ["Well,",  "as a matter
of fact it's", "very runny,
sir"],
    ["I think it's
runnier",  "than you",  "like it,
sir"]
]

from itertools import chain, izip_longest

matrix = chain.from_iterable(
    izip_longest(
        *(x.splitlines() for x in y), 
        fillvalue='') 
    for y in text)

然后应用上面的代码.

另见http://pypi.python.org/pypi/texttable

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