Django admin - 内联内联(或同时编辑三个模型) [英] Django admin - inline inlines (or, three model editing at once)

问题描述

我有一组看起来像这样的模型:

class Page(models.Model):标题=models.CharField(max_length=255)类 LinkSection(models.Model):页 = 模型.外键(页)标题=models.CharField(max_length=255)类链接(模型.模型):linksection = models.ForeignKey(LinkSection)text = models.CharField(max_length=255)url = 模型.URLField()

和一个看起来像这样的 admin.py:

class LinkInline(admin.TabularInline):模型 = 链接类 LinkSectionInline(admin.TabularInline):模型 = LinkSection内联 = [ LinkInline, ]类 PageAdmin(admin.ModelAdmin):内联 = [ LinkSectionInline, ]

我的目标是获得一个管理界面，让我可以在一个页面上编辑所有内容.这种模型结构的最终结果是将事物生成为一个视图+模板，看起来或多或少像:

{{page.title}}
{% for ls in page.linksection_set.objects.all %}<div><h2>{{ls.title}}</h2><ul>{% for l in ls.link_set.objects.all %}<li><a href="{{l.url}}">{{l.title}}</a></li>{% 结束为 %}

{% 结束为 %}

正如我所料，我知道 Django 管理员中的 inline-in-an-inline 技巧失败了.有谁知道允许这种三级模型编辑的方法?提前致谢.

解决方案

你需要创建一个自定义的表单 和模板 用于 LinkSectionInline.

这样的东西应该适用于表单:

LinkFormset = forms.modelformset_factory(Link)类 LinkSectionForm(forms.ModelForm):def __init__(self, **kwargs):super(LinkSectionForm, self).__init__(**kwargs)self.link_formset = LinkFormset(instance=self.instance,data=self.data 或 None,前缀=self.prefix)def is_valid(self):返回 (super(LinkSectionForm, self).is_valid() 和self.link_formset.is_valid())def save(self, commit=True):# 支持 commit=False 是另一种蠕虫.没用处# 在需要之前.(亚格尼)断言提交 == 真res = super(LinkSectionForm, self).save(commit=commit)self.link_formset.save()返回资源

(这只是从我的脑海中浮现出来的，没有经过测试，但它应该能让你朝着正确的方向前进.)

您的模板只需要适当地呈现表单和 form.link_formset.

I've got a set of models that look like this:

class Page(models.Model):
    title = models.CharField(max_length=255)

class LinkSection(models.Model):
    page = models.ForeignKey(Page)
    title = models.CharField(max_length=255)

class Link(models.Model):
    linksection = models.ForeignKey(LinkSection)
    text = models.CharField(max_length=255)
    url = models.URLField()

and an admin.py that looks like this:

class LinkInline(admin.TabularInline):
    model = Link
class LinkSectionInline(admin.TabularInline):
    model = LinkSection
    inlines = [ LinkInline, ]
class PageAdmin(admin.ModelAdmin):
    inlines = [ LinkSectionInline, ]

My goal is to get an admin interface that lets me edit everything on one page. The end result of this model structure is that things are generated into a view+template that looks more or less like:

<h1>{{page.title}}</h1>
{% for ls in page.linksection_set.objects.all %}
<div>
    <h2>{{ls.title}}</h2>
    <ul>
         {% for l in ls.link_set.objects.all %}
        <li><a href="{{l.url}}">{{l.title}}</a></li>
         {% endfor %}
    </ul>
</div>
{% endfor %}

I know that the inline-in-an-inline trick fails in the Django admin, as I expected. Does anyone know of a way to allow this kind of three level model editing? Thanks in advance.

解决方案

You need to create a custom form and template for the LinkSectionInline.

Something like this should work for the form:

LinkFormset = forms.modelformset_factory(Link)
class LinkSectionForm(forms.ModelForm):
    def __init__(self, **kwargs):
        super(LinkSectionForm, self).__init__(**kwargs)
        self.link_formset = LinkFormset(instance=self.instance, 
                                        data=self.data or None,
                                        prefix=self.prefix)

    def is_valid(self):
        return (super(LinkSectionForm, self).is_valid() and 
                    self.link_formset.is_valid())

    def save(self, commit=True):
        # Supporting commit=False is another can of worms.  No use dealing
        # it before it's needed. (YAGNI)
        assert commit == True 
        res = super(LinkSectionForm, self).save(commit=commit)
        self.link_formset.save()
        return res

(That just came off the top of my head and isn't tested, but it should get you going in the right direction.)

Your template just needs to render the form and form.link_formset appropriately.

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