通过 app_label 在子目录中建模? [英] Model in sub-directory via app_label?

问题描述

为了将我的模型放在子文件夹中，我尝试使用描述的 app_label Meta 字段 这里.

In order to place my models in sub-folders I tried to use the app_label Meta field as described here.

我的目录结构如下:

• 项目
  • 应用
    • 富
      • 模型
        • __init__.py
        • bar_model.py

        在 bar_model.py 中，我像这样定义我的模型:

        In bar_model.py I define my Model like this:

        from django.db import models
        
        class SomeModel(models.Model):
        
            field = models.TextField()
        
            class Meta:
                app_label = "foo"
        

        我可以像这样成功导入模型:

        I can successfully import the model like so:

        from apps.foo.models.bar_model import SomeModel
        

        但是，运行:

        ./manage.py syncdb
        

        不为模型创建表.然而，在详细模式下，我确实看到了应用程序foo"被正确识别(它位于 settings.py 的 INSTALLED_APPS 中).将模型移动到 foo 下的 models.py 确实有效.

        does not create the table for the model. In verbose mode I do see, however, that the app "foo" is properly recognized (it's in INSTALLED_APPS in settings.py). Moving the model to models.py under foo does work.

        是否有一些特定的约定没有在 app_label 或整个机制中记录，以防止该模型结构被同步数据库识别?

        Is there some specific convention not documented with app_label or with the whole mechanism that prevents this model structure from being recognized by syncdb?

        推荐答案

        查看 Django 票证 #10985:解释如何模型可以组织在一个目录中

        See Django ticket #10985: Explain how models can be organised in a directory

        可能是您没有将模型导入 __init__.py?

        It may be that you aren't importing your models into __init__.py?

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