JavaFX 周期性后台任务 [英] JavaFX periodic background task

问题描述

我尝试定期在 JavaFX 应用程序后台线程中运行，这会修改一些 GUI 属性.

I try to run in JavaFX application background thread periodically, which modifies some GUI property.

我想我知道如何使用 javafx.concurrent 中的 Task 和 Service 类，但不知道如何运行这样的不使用 Thread#sleep() 方法的周期性任务.如果我可以使用 Executors 中的一些 Executor 制造方法(Executors.newSingleThreadScheduledExecutor())

I think I know how to use Task and Service classes from javafx.concurrent and can't figure it out how to run such periodic task without using Thread#sleep() method. It would be nice if I can use some Executor from Executors fabricate methods (Executors.newSingleThreadScheduledExecutor())

我尝试每 5 秒运行一次 Runnable，这会重新启动 javafx.concurrent.Service 但它立即挂起 service.restart 甚至service.getState() 被调用.

I tried to run Runnable every 5 sec, which restarts javafx.concurrent.Service but it hangs immediately as service.restart or even service.getState() is called.

所以最后我使用 Executors.newSingleThreadScheduledExecutor()，它每 5 秒触发一次我的 Runnable 并且 Runnable 运行另一个 Runnable 使用:

So finally I use Executors.newSingleThreadScheduledExecutor(), which fires my Runnable every 5 sec and that Runnable runs another Runnable using:

Platform.runLater(new Runnable() {
 //here i can modify GUI properties
}

它看起来很糟糕:(有没有更好的方法来使用 Task 或 Service 类来做到这一点?

It looks very nasty :( Is there a better way to do this using Task or Service classes?

推荐答案

您可以为该任务使用时间轴:

You can use Timeline for that task:

Timeline fiveSecondsWonder = new Timeline(
                 new KeyFrame(Duration.seconds(5), 
                 new EventHandler<ActionEvent>() {

    @Override
    public void handle(ActionEvent event) {
        System.out.println("this is called every 5 seconds on UI thread");
    }
}));
fiveSecondsWonder.setCycleCount(Timeline.INDEFINITE);
fiveSecondsWonder.play();

对于后台进程(对 UI 不做任何事情)，您可以使用旧好的 java.util.Timer:

for the background processes (which don't do anything to the UI) you can use old good java.util.Timer:

new Timer().schedule(
    new TimerTask() {

        @Override
        public void run() {
            System.out.println("ping");
        }
    }, 0, 5000);

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