JS 在对象值中搜索 [英] JS search in object values

问题描述

我有一个像这样的同类对象数组；

<预><代码>[{"foo" : "酒吧",酒吧":坐"},{"foo" : "lorem","bar" : "ipsum"},{"foo" : "dolor","bar" : "amet"}]

我想用关键字搜索这些对象的值(而不是键)，并返回一个对象数组，其中包含任何值中的关键字.

例如，使用关键字r，我将获得所有对象(对象#1 中的baR"、对象#2 中的loRem"和对象#3 中的doloR").使用关键字 lo，我会得到对象 2 和 3(LOrem"和doLOr")，使用 a，我会得到对象 1 和 3，("bar"和Amet").但是，使用关键字 foo，我会得到一个空数组，因为foo"是一个键，并且在任何值中都找不到(与bar"不同)……你得到想法.

我该怎么做?非常感谢提前！

解决方案

是这样的:

var 对象 = [{"foo" : "酒吧",酒吧":坐"},{"foo" : "lorem","bar" : "ipsum"},{"foo" : "dolor","bar" : "amet"}];var 结果 = [];var toSearch = "lo";for(var i=0; i

结果数组将包含所有匹配的对象.

如果你搜索lo"，结果会是这样的:

[{ foo="lorem", bar="ipsum"}, { foo="dolor", bar="amet"}]

新版本 - 添加了修剪代码，确保结果集中没有重复的代码.

function trimString(s) {var l=0, r=s.length -1;while(l < s.length && s[l] == ' ') l++;while(r > l && s[r] == ' ') r-=1;返回 s.substring(l, r+1);}函数比较对象(o1，o2){var k = '';for(k in o1) if(o1[k] != o2[k]) 返回假；for(k in o2) if(o1[k] != o2[k]) 返回假；返回真；}功能项目存在(干草堆，针){for(var i=0; i<haystack.length; i++) if(compareObjects(haystack[i],needle)) return true;返回假；}var 对象 = [{"foo" : "酒吧",酒吧":坐"},{"foo" : "lorem","bar" : "ipsum"},{"foo" : "dolor blor","bar" : "amet blo"}];函数 searchFor(toSearch) {var 结果 = [];toSearch = trimString(toSearch);//修剪它for(var i=0; i

I have an array of homogeneous objects like so;

[
  {
    "foo" : "bar",
    "bar" : "sit"
  },
  {
    "foo" : "lorem",
    "bar" : "ipsum"
  },
  {
    "foo" : "dolor",
    "bar" : "amet"
  }
]

I'd like to search these objects' values (not keys) with a keyword, and return an array of objects that contain the keyword in any of the values.

So for example, with a keyword r, I would get all the objects ("baR" in object #1, "loRem" in object #2 and "doloR" in object #3). With a keyword lo, I would get objects 2 and 3 ("LOrem" and "doLOr"), with a, I'd get objects 1 and 3, ("bAr" and "Amet"). With the keyword foo however, I would get an empty array, since "foo" is a key, and isn't found in any of the values (unlike "bar")... you get the idea.

How would I go about doing this? Thanks a lot in advance!

解决方案

Something like this:

var objects = [
  {
    "foo" : "bar",
    "bar" : "sit"
  },
  {
    "foo" : "lorem",
    "bar" : "ipsum"
  },
  {
    "foo" : "dolor",
    "bar" : "amet"
  }
];

var results = [];

var toSearch = "lo";

for(var i=0; i<objects.length; i++) {
  for(key in objects[i]) {
    if(objects[i][key].indexOf(toSearch)!=-1) {
      results.push(objects[i]);
    }
  }
}

The results array will contain all matched objects.

If you search for 'lo', the result will be like:

[{ foo="lorem", bar="ipsum"}, { foo="dolor", bar="amet"}]

NEW VERSION - Added trim code, code to ensure no duplicates in result set.

function trimString(s) {
  var l=0, r=s.length -1;
  while(l < s.length && s[l] == ' ') l++;
  while(r > l && s[r] == ' ') r-=1;
  return s.substring(l, r+1);
}

function compareObjects(o1, o2) {
  var k = '';
  for(k in o1) if(o1[k] != o2[k]) return false;
  for(k in o2) if(o1[k] != o2[k]) return false;
  return true;
}

function itemExists(haystack, needle) {
  for(var i=0; i<haystack.length; i++) if(compareObjects(haystack[i], needle)) return true;
  return false;
}

var objects = [
  {
    "foo" : "bar",
    "bar" : "sit"
  },
  {
    "foo" : "lorem",
    "bar" : "ipsum"
  },
  {
    "foo" : "dolor blor",
    "bar" : "amet blo"
  }
];

function searchFor(toSearch) {
  var results = [];
  toSearch = trimString(toSearch); // trim it
  for(var i=0; i<objects.length; i++) {
    for(var key in objects[i]) {
      if(objects[i][key].indexOf(toSearch)!=-1) {
        if(!itemExists(results, objects[i])) results.push(objects[i]);
      }
    }
  }
  return results;
}

console.log(searchFor('lo '));

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