使用 Java 在二进制文件中搜索字节序列 [英] Searching for a sequence of Bytes in a Binary File with Java

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问题描述

我必须使用 Java 在一组二进制文件中搜索一个字节序列.

I have a sequence of bytes that I have to search for in a set of Binary files using Java.

示例:我在二进制文件中搜索字节序列 DEADBEEF(十六进制).我将如何在 Java 中执行此操作?是否有内置方法,例如用于二进制文件的 String.contains() ?

Example: I'm searching for the byte sequence DEADBEEF (in hex) in a Binary file. How would I go about doing this in Java? Is there a built-in method, like String.contains() for Binary files?

推荐答案

不,没有内置方法可以做到这一点.但是,直接从HERE复制(应用了两个修复到原始代码):

No, there is no built-in method to do that. But, directly copied from HERE (with two fixes applied to the original code):

/**
 * Knuth-Morris-Pratt Algorithm for Pattern Matching
 */
class KMPMatch {
    /**
     * Finds the first occurrence of the pattern in the text.
     */
    public static int indexOf(byte[] data, byte[] pattern) {
        if (data.length == 0) return -1;

        int[] failure = computeFailure(pattern);    
        int j = 0;

        for (int i = 0; i < data.length; i++) {
            while (j > 0 && pattern[j] != data[i]) {
                j = failure[j - 1];
            }
            if (pattern[j] == data[i]) { j++; }
            if (j == pattern.length) {
                return i - pattern.length + 1;
            }
        }
        return -1;
    }

    /**
     * Computes the failure function using a boot-strapping process,
     * where the pattern is matched against itself.
     */
    private static int[] computeFailure(byte[] pattern) {
        int[] failure = new int[pattern.length];

        int j = 0;
        for (int i = 1; i < pattern.length; i++) {
            while (j > 0 && pattern[j] != pattern[i]) {
                j = failure[j - 1];
            }
            if (pattern[j] == pattern[i]) {
                j++;
            }
            failure[i] = j;
        }

        return failure;
    }
}

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