在 Java Servlet 中获取通过 jquery ajax 发送的参数 [英] Get parameter sent via jquery ajax in Java Servlet
问题描述
我在网上搜索了这个主题,但我找不到一个有效的例子.如果有人能给我帮助,我会很高兴.
I search this topic on web but I can't get a example that worked. I will be gladed with someone could give me a help.
这是我测试的.
$.ajax({
url: 'GetJson',
type: 'POST',
dataType: 'json',
contentType: 'application/json',
data: {id: 'idTest'},
success: function(data) {
console.log(data);
}
});
在 Sevlet
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String id = request.getParameter("id");
String id2[] = request.getParameterValues("id");
String id3 = request.getHeader("id");
}
我的一切都变得空了.
推荐答案
排序答案是这个数据隐藏在请求InputStream
中.
The sort answer is that this data is hidden in the request InputStream
.
以下 servlet 演示了如何使用它(我在 JBoss 7.1.1 上运行它):
The following servlet is a demo of how you can use this (I am running it on a JBoss 7.1.1):
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.UnsupportedEncodingException;
import java.net.URLDecoder;
import java.util.Enumeration;
import java.util.HashMap;
import java.util.Map;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet(name="fooServlet", urlPatterns="/foo")
public class FooServlet extends HttpServlet
{
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
InputStream is = req.getInputStream();
ByteArrayOutputStream os = new ByteArrayOutputStream();
byte[] buf = new byte[32];
int r=0;
while( r >= 0 ) {
r = is.read(buf);
if( r >= 0 ) os.write(buf, 0, r);
}
String s = new String(os.toByteArray(), "UTF-8");
String decoded = URLDecoder.decode(s, "UTF-8");
System.err.println(">>>>>>>>>>>>> DECODED: " + decoded);
System.err.println("================================");
Enumeration<String> e = req.getParameterNames();
while( e.hasMoreElements() ) {
String ss = (String) e.nextElement();
System.err.println(" >>>>>>>>> " + ss);
}
System.err.println("================================");
Map<String,String> map = makeQueryMap(s);
System.err.println(map);
//////////////////////////////////////////////////////////////////
//// HERE YOU CAN DO map.get("id") AND THE SENT VALUE WILL BE ////
//// RETURNED AS EXPECTED WITH request.getParameter("id") ////
//////////////////////////////////////////////////////////////////
System.err.println("================================");
resp.setContentType("application/json; charset=UTF-8");
resp.getWriter().println("{'result':true}");
}
// Based on code from: http://www.coderanch.com/t/383310/java/java/parse-url-query-string-parameter
private static Map<String, String> makeQueryMap(String query) throws UnsupportedEncodingException {
String[] params = query.split("&");
Map<String, String> map = new HashMap<String, String>();
for( String param : params ) {
String[] split = param.split("=");
map.put(URLDecoder.decode(split[0], "UTF-8"), URLDecoder.decode(split[1], "UTF-8"));
}
return map;
}
}
随着请求:
$.post("foo",{id:5,name:"Nikos",address:{city:"Athens"}})
输出为:
>>>>>>>>>>>>> DECODED: id=5&name=Nikos&address[city]=Athens
================================
================================
{address[city]=Athens, id=5, name=Nikos}
================================
(注意:req.getParameterNames()
不起作用.第 4 行打印的地图包含使用 request.getParameter()
通常可以访问的所有数据.注意还有嵌套的对象符号,{address:{city:"Athens"}}
→ address[city]=Athens
)
(NOTE: req.getParameterNames()
does not work. The map printed in the 4th line contains all the data normally accessible using request.getParameter()
. Note also the nested object notation, {address:{city:"Athens"}}
→ address[city]=Athens
)
与您的问题略有关系,但为了完整起见:
Slightly unrelated to your question, but for the sake of completeness:
如果你想使用服务器端的 JSON 解析器,你应该对数据使用 JSON.stringify
:
If you want to use a server-side JSON parser, you should use JSON.stringify
for the data:
$.post("foo",JSON.stringify({id:5,name:"Nikos",address:{city:"Athens"}}))
在我看来,与服务器通信 JSON 的最佳方式是使用 JAX-RS(或 Spring 等价物).它在现代服务器上非常简单并且可以解决这些问题.
In my opinion the best way to communicate JSON with the server is using JAX-RS (or the Spring equivalent). It is dead simple on modern servers and solves these problems.
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