如何仅从命名号码(没有名称)中提取号码? [英] How do I extract just the number from a named number (without the name)?

问题描述

我只是在寻找 B1(newx) 线性模型系数的值，而不是名称.我只想要 0.5 的值.我不想要newx"这个名字.

I am looking for just the value of the B1(newx) linear model coefficient, not the name. I just want the 0.5 value. I do not want the name "newx".

newx <- c(0.5,1.5.2.5)

newy <- c(2,3,4)

out <- lm(newy ~ newx)

out 看起来像:

Call:
lm(formula = newy ~ newx)

Coefficients:
(Intercept)         newx  
       1.5         1.0  

我到了这里.但现在我卡住了.

I arrived here. But now I am stuck.

out$coefficients["newx"]

newx 

1.0 

推荐答案

对于这样的单个元素，使用 [[ 而不是 [.比较:

For a single element like this, use [[ rather than [. Compare:

coefficients(out)["newx"]
# newx 
#    1 

coefficients(out)[["newx"]]
# [1] 1

更一般地，使用unname():

unname(coefficients(out)[c("newx", "(Intercept)")])
# [1] 1.0 1.5

head(unname(mtcars))
#                     NA NA  NA  NA   NA    NA    NA NA NA NA NA
# Mazda RX4         21.0  6 160 110 3.90 2.620 16.46  0  1  4  4
# Mazda RX4 Wag     21.0  6 160 110 3.90 2.875 17.02  0  1  4  4
# Datsun 710        22.8  4 108  93 3.85 2.320 18.61  1  1  4  1
# Hornet 4 Drive    21.4  6 258 110 3.08 3.215 19.44  1  0  3  1
# Hornet Sportabout 18.7  8 360 175 3.15 3.440 17.02  0  0  3  2
# Valiant           18.1  6 225 105 2.76 3.460 20.22  1  0  3  1

## etc.

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