我可以在 Javascript 中定义自定义运算符重载吗? [英] Can I define custom operator overloads in Javascript?

问题描述

是否可以在 JavaScript 中的类型实例之间定义自定义运算符?

Is it possible to define custom operators between instances of a type in JavaScript?

例如，假设我有一个自定义向量类，是否可以使用

For example, given that I have a custom vector class, is it possible to use

vect1 == vect2

检查相等性，而底层代码是这样的?

to check for equality, whilst the underlying code would be something like this?

operator ==(a, b) {
    return a.x == b.x && a.y == b.y && a.z == b.z;
}

(当然这是废话.)

推荐答案

我同意向量原型上的相等函数是最好的解决方案.请注意，您还可以通过链接构建其他类似中缀的运算符.

I agree that the equal function on the vector prototype is the best solution. Note that you can also build other infix-like operators via chaining.

function Vector(x, y, z) {
    this.x = x;
    this.y = y;
    this.z = z;
}

Vector.prototype.add = function (v2) {
    var v = new Vector(this.x + v2.x,
                       this.y + v2.y,
                       this.z + v2.z);
    return v;
}

Vector.prototype.equal = function (v2) {
    return this.x == v2.x && this.y == v2.y && this.z == v2.z;
}

您可以在此处查看在线示例.

更新:这是创建工厂函数的更广泛示例支持链接.

Update: Here's a more extensive sample of creating a Factory function that supports chaining.

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