CakePHP 检查用户是否在视图中登录 [英] CakePHP check if user is logged in inside a view

问题描述

我有以下代码:

    <?php

    if (!$this->Auth->user())
    {
        echo $this->element('header');
    }
    else
    {
        echo $this->element('header-bar');
    }

    ?>

在我的视图中，它应该为登录用户显示不同的标题，但会引发以下错误:

inside my view which should show a different header for logged in users but throws the following error:

Notice (8): Undefined property: View::$Auth [APP/views/layouts/page.ctp, line 17]
Fatal error: Call to a member function user() on a non-object in /Users/cameron/Sites/thehive/app/views/layouts/page.ctp on line 17

我该如何解决这个问题?谢谢

How do I fix this? Thanks

推荐答案

注意: 另请查看 meotimdihia 的 下面的答案.它获得了很多的赞成票.

Note: Also check out meotimdihia's answer below. It's got a lot of upvotes.

Auth 组件用于控制器.您需要在控制器中检查授权，然后为视图设置一个变量，例如 $this->set('authUser', $this->Auth->user());.然后在您看来，您可以执行以下操作:

The Auth component is for use in the Controller. You'll want to check for authorization in the controller, then set a variable for the view, e.g., $this->set('authUser', $this->Auth->user());. Then in your view you can do:

if (!$authUser)
{
    echo $this->element('header');
}

如果您希望为所有控制器方法自动完成此操作，您可以考虑修改 cake/libs/controller/app_controller.php 以使其包含 Auth 组件.

If you want this to be done automatically for all controller methods, you can look into modifying cake/libs/controller/app_controller.php so that it includes the Auth component.

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