将对象列表写入文件 [英] write list of objects to a file

问题描述

我有以下格式的班级推销员:

I've got a class salesman in the following format:

class salesman
{
    public string name, address, email;
    public int sales;
}

我有另一个类，用户可以在其中输入姓名、地址、电子邮件和销售额.然后将此输入添加到列表中

I've got another class where the user inputs name, address, email and sales. This input is then added to a list

List<salesman> salesmanList = new List<salesman>();

在用户将尽可能多的销售员输入列表后，他们可以选择将列表保存到他们选择的文件中(我可以将其限制为 .xml 或 .txt(哪个更合适)).我如何将此列表添加到文件中?此外，如果用户希望稍后查看记录，则需要将该文件重新读回列表中.

After the user has input as many salesman to the list as they like, they have the option to save the list to a file of their choice (which I can limit to .xml or .txt(which ever is more appropriate)). How would I add this list to the file? Also this file needs to be re-read back into a list if the user wishes to later view the records.

推荐答案

这样的事情会起作用.这使用二进制格式(加载速度最快)，但相同的代码适用于具有不同序列化程序的 xml.

Something like this would work. this uses a binary format (the fastest for loading) but the same code would apply to xml with a different serializer.

using System.IO;

    [Serializable]
    class salesman
    {
        public string name, address, email;
        public int sales;
    }

    class Program
    {
        static void Main(string[] args)
        {
            List<salesman> salesmanList = new List<salesman>();
            string dir = @"c:	emp";
            string serializationFile = Path.Combine(dir, "salesmen.bin");

            //serialize
            using (Stream stream = File.Open(serializationFile, FileMode.Create))
            {
                var bformatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();

                bformatter.Serialize(stream, salesmanList);
            }

            //deserialize
            using (Stream stream = File.Open(serializationFile, FileMode.Open))
            {
                var bformatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();

                List<salesman>  salesman = (List<salesman>)bformatter.Deserialize(stream);
            }
        }
    }

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