保存前编辑 django-rest-framework 序列化程序对象 [英] Editing django-rest-framework serializer object before save

查看:29
本文介绍了保存前编辑 django-rest-framework 序列化程序对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想在保存之前编辑 django-rest-framework 序列化程序对象.这就是我目前的做法 -

I want to edit a django-rest-framwork serializer object before it is saved. This is how I currently do it -

def upload(request):
    if request.method == 'POST':
        form = ImageForm(request.POST, request.FILES)
        if form.is_valid(): # All validation rules pass
             obj = form.save(commit=False)
             obj.user_id = 15
             obj.save()

如何使用 django-rest-framework 序列化器对象来实现?

How can I do it with a django-rest-framework serializer object?

@api_view(['POST','GET'])
def upload_serializers(request):
    if request.method == 'POST':
         serializer = FilesSerializer(data=request.DATA, files=request.FILES)
         if serializer.is_valid():
              serializer.save()

推荐答案

您可以在保存序列化程序之前编辑序列化程序的对象:

You can edit the serializer's object before save the serializer:

if serializer.is_valid():
    serializer.object.user_id = 15 # <----- this line
    serializer.save()

这篇关于保存前编辑 django-rest-framework 序列化程序对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
相关文章
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆