findspark.init() IndexError: list index out of range 错误 [英] findspark.init() IndexError: list index out of range error
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问题描述
在 Python 3.5 Jupyter 环境中运行以下命令时,出现以下错误.关于导致它的原因有什么想法吗?
When running the following in a Python 3.5 Jupyter environment I get the error below. Any ideas on what is causing it?
import findspark
findspark.init()
错误:
IndexError Traceback (most recent call
last) <ipython-input-20-2ad2c7679ebc> in <module>()
1 import findspark
----> 2 findspark.init()
3
4 import pyspark
/.../anaconda/envs/pyspark/lib/python3.5/site-packages/findspark.py in init(spark_home, python_path, edit_rc, edit_profile)
132 # add pyspark to sys.path
133 spark_python = os.path.join(spark_home, 'python')
--> 134 py4j = glob(os.path.join(spark_python, 'lib', 'py4j-*.zip'))[0]
135 sys.path[:0] = [spark_python, py4j]
136
IndexError: list index out of range
推荐答案
这很可能是因为 SPARK_HOME
环境变量没有在您的系统上正确设置.或者,您可以在初始化 findspark
时指定它,如下所示:
This is most likely due to the SPARK_HOME
environment variable not being set correctly on your system. Alternatively, you can just specify it when you're initialising findspark
, like so:
import findspark
findspark.init('/path/to/spark/home')
在那之后,它应该一切正常!
After that, it should all work!
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