servlet 的根 URL [英] Root URl of the servlet

问题描述

我想从 servlet 之一获取我的 Web 应用程序的根 url.

I want to get the root url of my web application from one of the servlet.

如果我在www.mydomain.com"中部署我的应用程序，我想获得像http://www.mydomain.com".

If I deploy my application in "www.mydomain.com" I want to get the root url like "http://www.mydomain.com".

同样的事情，如果我将它部署在具有 8080 端口的本地 tomcat 服务器中，它应该给 http://localhost:8080/myapp

Same thing if I deploy it in local tomcat server with 8080 port it should give http://localhost:8080/myapp

谁能告诉我如何从 servlet 获取我的 Web 应用程序的根 URL?

Can anyone tell me how to get the root URL of my web application from servlet?

public class MyServlet extends HttpServlet {

    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

        String rootURL="";
        //Code to get the URL where this servlet is deployed

    }
}

推荐答案

您确实意识到客户端看到的 URL(和/或在他的浏览器中键入)和部署 servlet 的容器所提供的 URL 可能非常不同?

You do realize that the URL client sees (and/or types into his browser) and the URL served by the container your servlet is deployed on can be very different?

不过，为了获得后者，您可以在 HttpServletRequest:

In order to get the latter, though, you have a few methods available on HttpServletRequest:

• 您可以调用 getScheme()、getServerName()、getServerPort() 和 getContextPath()并使用适当的分隔符将它们组合起来
• 或者您可以调用 getRequestURL() 并从中删除 getServletPath() 和 getPathInfo().

• You can either call getScheme(), getServerName(), getServerPort() and getContextPath() and combine them using appropriate separators
• OR you can call getRequestURL() and remove getServletPath() and getPathInfo() from it.

这篇关于servlet 的根 URL的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！