Javascript 计数选中复选框 [英] Javascript count checked checkbox

问题描述

我知道@stackoverflow 可能有一些类似的问题，但我还没有找到任何解决我的问题的方法 :s

I know that may have a few similar questions @stackoverflow, but I didnt found any solution to my problem yet :s

<?php
while($rowVideo = mysql_fetch_array($ResultQueryVideo))
{
?>
<input type="checkbox" name = "checkbox-1[]" class="checkbox" value ="<?php echo $rowVideo['idVideo'] ?>" /> <?php....some code...

这会产生几个复选框，与 idVideo 的数字相同..这就是重点.

This results a few checkbox's, the same number as idVideo..thats the point.

现在，在提交之前，我需要确保至少选中了一个复选框.但我没有成功 :x

Now, before the submit, I need to be sure that at least one checkbox is checked. But i was not sucesseful :x

function isCountCheck (helperMsg) {
    var chkCnt = 0;
    var Frm = document.forms[0];
    var dLen = Frm.length - 1;
    for (i=0;i<=dLen;i++) {
        if(document.form1.["checkbox-1[]"].checked) chkCnt++;
    }

    if (chkCnt>0) {
        return true;
    } else {
        alert(helperMsg);
        return false;
    }
}

额外的细节:表单名称 = "form1"

Extra details: form name = "form1"

你能指导我一下吗?谢谢

Can you guide me a litle ? Thanks

function isCountCheck(){
    if($("input[type=checkbox]:checked").length > 0)
    {
    return true;
    }
    else
    {
    alert('Invalid');
    return false;
    }
}

但仍然无法正常工作..即使显示该警报..

But still not working..even that alert is shown..

推荐答案

主要问题是您没有在循环中使用 i 索引来引用各个复选框，并且您已经在 [ 之前得到了一个 .，这是一个语法错误.所以改变:

The main problem is that you're not using the i index within the loop to reference the individual checkboxes, and you've got a . just before the [ which is a syntax error. So change:

if(document.form1.["checkbox-1[]"].checked) chkCnt++;

致:

if(document.form1["checkbox-1[]"][i].checked) chkCnt++;

但是你可以稍微整理一下函数如下:

But you can neaten up the function somewhat as follows:

function isCountCheck(helperMsg) {
    var i, dLen = document.form1["checkbox-1[]"].length;
    // if the length property is undefined there is only one checkbox
    if (typeof dLen === "undefined") {
        if (document.form1["checkbox-1[]"].checked) return true;
    }
    else {
        for (i = 0; i < dLen; i++) {
            if (document.form1["checkbox-1[]"][i].checked) return true;
        }
    }
    alert(helperMsg);
    return false;
}

演示:http://jsfiddle.net/nnnnnn/ZjK3w/1/

或者只是遍历表单中的所有输入，检查每个输入的类型(和/或名称):

Or just loop through all inputs in the form, checking the type (and/or the name) of each one:

function isCountCheck(helperMsg) {
    var i, len, inputs = document.form1.getElementsByTagName("input");
    for (i = 0, len = inputs.length; i < len; i++) {
        if (inputs[i].type === "checkbox"
            && inputs[i].checked)
            return true;
    }
    alert(helperMsg);
    return false;
}

演示:http://jsfiddle.net/nnnnnn/ZjK3w/2/

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