如果未禁用,则 Jquery 全选 [英] Jquery select all if not disabled
问题描述
我正在使用以下脚本选择具有给定类的所有复选框.
I am using the following script to select all checkboxes with a given class.
$(document).ready(function(){ // 1
// 2
$(':checkbox.selectall').on('click', function(){
// 3
$(':checkbox[class='+ $(this).data('checkbox-name') + ']').prop("checked", $(this).prop("checked"));
$(':checkbox[class='+ $(this).data('checkbox-name') + ']').trigger("change");
});
});
但是我遇到了一个问题,因为取消/全选复选框能够取消/选择被禁用的复选框.
However I'm having a problem as the de/select all checkbox is able to de/select checkboxes which are disabled.
我试过了
$(document).ready(function(){ // 1
// 2
$(':checkbox.selectall').on('click', function(){
// 3
$(':checkbox[class='+ $(this).data('checkbox-name') + !$(:disabled) + ']').prop("checked", $(this).prop("checked"));
$(':checkbox[class='+ $(this).data('checkbox-name') + !$(:disabled) + ']').trigger("change");
});
});
但它不起作用.我做了一个 jsfiddle 来展示这个问题 http://jsfiddle.net/e67Fv/
But it does not work. I have made a jsfiddle to showcase the problem http://jsfiddle.net/e67Fv/
推荐答案
嗯...有趣的尝试,但你不能在选择器中使用 jQuery 对象,因为选择器只是一个普通的字符串.
Hm... interresting attempt, but you can't use a jQuery object inside a selector, as the selector is just a plain string.
用于排除禁用元素的选择器将是 :not(:disabled)
,因此您的代码应该是:
The selector for excluding the disabled elements would be :not(:disabled)
, so your code should be:
$(document).ready(function(){
$(':checkbox.selectall').on('click', function(){
$(':checkbox[class='+ $(this).data('checkbox-name') + ']:not(:disabled)').prop("checked", $(this).prop("checked"));
$(':checkbox[class='+ $(this).data('checkbox-name') + ']:not(:disabled)').trigger("change");
});
});
请注意,您可以链接调用,因此您不必选择项目两次:
Note that you can chain calls, so you don't have to select the items twice:
$(document).ready(function(){
$(':checkbox.selectall').on('click', function(){
$(':checkbox[class='+ $(this).data('checkbox-name') + ']:not(:disabled)').prop("checked", $(this).prop("checked")).trigger("change");
});
});
这篇关于如果未禁用,则 Jquery 全选的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!