如何在 Objective-C 中传递多个参数? [英] How do I pass multiple parameters in Objective-C?

问题描述

我已经阅读了一些关于 Objective-C 方法语法的帖子，但我想我不明白一个方法的多个名称.

I have read several of the post about Objective-C method syntax but I guess I don't understand multiple names for a method.

我正在尝试创建一个名为 getBusStops 的方法，它带有 NSString 和 NSTimeInterval 参数，返回类型为 NSMutableArray.这是我构造方法的方式，但它显然在运行时出错:

I'm trying to create a method called getBusStops with NSString and NSTimeInterval parameters and a return type of NSMutableArray. This is how I have constructed the method but it obviously gets errors at runtime:

- (NSMutableArray *)getBusStops:(NSString *)busStop
                                (NSTimeInterval *)timeInterval;

我看到了另一个使用方法的例子:

I saw another example with a method:

-(NSInteger)pickerView:(UIPickerView *)pickerView
            numberOfRowsInComponent:(NSInteger)component

我不明白为什么这个方法的每个参数都有一个方法名称.我应该对类似的事情做同样的事情:

I don't understand why this method has a method name for each parameter. Should I do the same with something like:

- (NSMutableArray *)getBusStops:(NSString *)busStop
                        forTime:(NSTimeInterval *)timeInterval

推荐答案

Objective-C 没有命名参数，因此冒号左侧的所有内容都是方法名称的一部分.例如，

Objective-C doesn't have named parameters, so everything on the left side of a colon is part of the method name. For example,

getBusStops: forTime:

是方法的名称.名称已拆分，因此可以更具描述性.你可以简单地命名你的方法

is the name of the method. The name is broken up so it can be more descriptive. You could simply name your method

getBusStops: :

但这并没有告诉你太多关于第二个参数的信息.

but that doesn't tell you much about the second parameter.

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