如何延迟调用具有多个参数的方法 [英] how to call a method of multiple arguments with delay

问题描述

我试图在延迟一段时间后调用一个方法.

I'm trying to call a method after some delay.

我知道有一个解决方案:

I know there is a solution for that:

[self performSelector:@selector(myMethod) withObject:nil afterDelay:delay];

我看到了这个问题和文档

但我的问题是:如何调用带有两个参数的方法??

But my question is: How can I call a method that takes two parameters??

例如:

- (void) MoveSomethigFrom:(id)from To:(id)to;

我将如何延迟调用此方法，使用 performSelector:withObject:afterDelay:

How would I call this method with delay, using performSelector:withObject:afterDelay:

谢谢

推荐答案

use dispatch_after:

use dispatch_after:

double delayInSeconds = 2.0;
dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, delayInSeconds * NSEC_PER_SEC);
dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
    //code to be executed on the main queue after delay
    [self MoveSomethingFrom:from To:to];
});

EDIT 2015:对于 Swift，我建议使用这个小助手方法:dispatch_after- 快速 GCD?

EDIT 2015: For Swift, i recommend using this small helper method: dispatch_after - GCD in swift?

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