如何通过仅从与第一个数组具有相同键的第二个数组中接管值来合并两个数组? [英] How to merge two arrays by taking over only values from the second array that has the same keys as the first one?

问题描述

我想合并两个数组:

$filtered = array(1 => 'a', 3 => 'c');
$changed = array(2 => 'b*', 3 => 'c*');

而合并应包括 $filtered 的所有元素和 $changed 的所有元素，这些元素在 $filtered 中有相应的键:

Whereas the merge should include all elements of $filtered and all those elements of $changed that have a corresponding key in $filtered:

$merged = array(1 => 'a', 3 => 'c*');

array_merge($filtered, $changed) 也会将 $changed 的附加键添加到 $filtered 中.所以不太合适.

array_merge($filtered, $changed) would add the additional keys of $changed into $filtered as well. So it does not really fit.

我知道我可以使用 $keys = array_intersect_key($filtered, $changed) 来获取两个数组中存在的键，这已经完成了一半的工作.

I know that I can use $keys = array_intersect_key($filtered, $changed) to get the keys that exist in both arrays which is already half of the work.

但是我想知道是否有任何(本机)函数可以将 $changed 数组减少为具有 array_intersect_key 指定的 $keys 的数组?我知道我可以使用带有回调函数的 array_filter 并检查其中的 $keys，但可能还有其他一些纯本机函数来仅从数组中提取那些元素可以指定键吗?

However I'm wondering if there is any (native) function that can reduce the $changed array into an array with the $keys specified by array_intersect_key? I know I can use array_filter with a callback function and check against $keys therein, but there is probably some other purely native function to extract only those elements from an array of which the keys can be specified?

我这么问是因为原生函数通常比带有回调的 array_filter 快得多.

I'm asking because the native functions are often much faster than array_filter with a callback.

推荐答案

如果我正确理解你的逻辑，应该这样做:

This should do it, if I'm understanding your logic correctly:

array_intersect_key($changed, $filtered) + $filtered

<小时>

实施:

$filtered = array(1 => 'a', 3 => 'c');
$changed = array(2 => 'b*', 3 => 'c*');
$expected = array(1 => 'a', 3 => 'c*');    
$actual = array_key_merge_deceze($filtered, $changed);

var_dump($expected, $actual);

function array_key_merge_deceze($filtered, $changed) {
    $merged = array_intersect_key($changed, $filtered) + $filtered;
    ksort($merged);
    return $merged;
}

输出:

Expected:
array(2) {
  [1]=>
  string(1) "a"
  [3]=>
  string(2) "c*"
}

Actual:
array(2) {
  [1]=>
  string(1) "a"
  [3]=>
  string(2) "c*"
}

这篇关于如何通过仅从与第一个数组具有相同键的第二个数组中接管值来合并两个数组?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！