ScriptManager的立即运行脚本 [英] ScriptManager run script immediately

问题描述

我有一个更新面板加载用户的控制，这里的目标是有所谓的这个时候发生了特定的JavaScript函数。我在想这会通过脚本管理器来完成，虽然这并不需要是如果有一个HTML替代的情况。

流动基本上是以下内容：

• 用户点击按钮


• 更新面板负载控制


• JavaScript函数叫做

非常感谢

我已经尝试过的RegisterStartupScript（..），虽然我可能已经做出了错误的语法

 如果（显示）
{
    字符串scriptId =的String.Format（{0}：脚本，++ uniquePopupId）;
    字符串scriptTag =的String.Format（showPopup（{0}，{1}）;，宽度，高度）;
    ScriptManager.RegisterStartupScript（这一点，this.GetType（），scriptId，scriptTag，真正的）;
}
 

解决方案：

 如果（显示）
{
    字符串scriptId =的String.Format（{0}：脚本，++ uniquePopupId）;
    字符串scriptTag =的String.Format（showPopup（{0}，{1}）;，宽度，高度）;
    ScriptManager.RegisterStartupScript（updPanelChildControl，updPanelChildControl.GetType（），scriptId，scriptTag，真正的）;
}
 

解决方案

使用

  ScriptManager.RegisterStartupScript（myControlInstance，
                                    typeof运算（MyControl）
                                     键，
                                     我的JavaScript字符串这里
                                     真正）;
 

这里。

I have an update panel load a user control, and the goal here is to have a specific JavaScript function called when this occurred. I was thinking this would be done through the Script Manager, though this does not need to be the case if there's an html alternative.

The flow is basically the following:

• User clicks button
• Update panel loads control
• Javascript function is called

Many thanks

I've already tried RegisterStartupScript(..), though i may have made a syntactical mistake

if (show)
{ 
    string scriptId = String.Format("{0}:script", ++uniquePopupId);
    string scriptTag = String.Format("showPopup({0},{1});", Width, Height);
    ScriptManager.RegisterStartupScript(this, this.GetType(), scriptId, scriptTag, true);
}

Solution:

if (show)
{ 
    string scriptId = String.Format("{0}:script", ++uniquePopupId);
    string scriptTag = String.Format("showPopup({0},{1});", Width, Height);
    ScriptManager.RegisterStartupScript(updPanelChildControl, updPanelChildControl.GetType(), scriptId, scriptTag, true);
}

解决方案

Use

ScriptManager.RegisterStartupScript(myControlInstance, 
                                    typeof(MyControl),
                                     "key",
                                     "my javascript string here", 
                                     true);

Documentation here.

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