Groovy 自定义按值对地图进行排序 [英] Groovy custom sort a map by value

问题描述

我有一张地图，例如

m=[
     "james":"silly boy",
     "janny":"Crazy girl",
     "jimmy":"funny man",
     "georges":"massive fella"
];

我想按地图的值对其进行排序，但忽略大小写(这就是为什么需要自定义排序的真正原因).因此我想我必须使用闭包来实现自定义排序.但我是 Groovy 的新手，一直在努力完成这项非常简单的任务！

I want to sort this map by its value but ignoring the case (this is really why the custom sort is needed). Hence I figured I had to implement a custom sort using a closure. But I'm brand new at Groovy and been struggling to get this very simple task done!

想要的结果是:

["janny":"Crazy girl", "jimmy":"funny man", "georges":"massive fella", "james":"silly boy"]

谢谢！

推荐答案

要排序不区分大小写，请使用

To sort with case insensitive, use

m.sort { it.value.toLowerCase() }

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