Jenkins 使用 Groovy 读取 Jenkinsfile 中文件的特定行 [英] Jenkins Read a Specific Line of a File in Jenkinsfile with Groovy

问题描述

我正在尝试使用 Groovy 读取 Jenkins stage 中 html 文件的特定行并将其内容保存到环境变量.问题是，File 和 readLines() 是不允许的.

I am trying to read a specific line of an html file in a Jenkins stage with Groovy and save its contents to an environment variable. The problem is, File and readLines() are not allowed.

我可以加载文件

env.WORKSPACE = pwd()
def file = readFile "${env.WORKSPACE}/file.html"

在本答案中提供

但是我怎样才能立即访问 n 行的内容?我正在使用 Jenkins 2.32

But how can I access instantly to the contents of line n? I am using Jenkins 2.32

推荐答案

我尝试了评论中 tim_yates 的建议，但 System 也被禁止.最终对我有用的只是将 System.getProperty("line.separator") 更改为换行符 " ".

I Tried the suggestion of tim_yates from the comments but System was also forbidden. What ultimately worked for me was just changing System.getProperty("line.separator") to new line character " ".

所以完整的答案在于它的简单性:

So the full answer was in its simplicity:

file.split("
")[n]

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