c++ - 如何在c/c++中使用指针传递结构数组? [英] How to pass an array of struct using pointer in c/c++?
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问题描述
在 C 代码中,我坚持将结构数组传递给函数,这是类似于我的问题的代码:
<前>类型定义结构{整数 x;输入 y;字符 *str1;字符 *str2;}结构1;void processFromStruct1(Struct1 *content[]);int main(){结构 1 mydata[]={ {1,1,"black","cat"},{4,5,"red","bird"},{6,7,"brown","fox"},};processFromStruct1(mydata);//如何?!??找不到正确的语法返回0;}void processFromStruct1(Struct1 *content[]){printf("%s", content[1]->str1);//如果我想打印'red',这样对吗?...}msvc 中的编译错误是这样的:
<前>错误 C2664:processFromStruct1":无法将参数 1 从Struct1 [3]"转换为Struct1 *[]"1> 指向的类型是不相关的;转换需要 reinterpret_cast、C-style cast 或 function-style cast如何解决这个问题?tnx.
解决方案
你几乎已经拥有了,要么这个
void processFromStruct1(Struct1 *content);
或者这个
void processFromStruct1(Struct1 content[]);
并且,正如 Alok 在评论中指出的那样,改变这个
content[1]->str1
到这里
content[1].str1
你的数组是一个结构数组,而不是一个指针数组,所以一旦你用 [1] 选择了一个特定的结构,就不需要进一步取消引用它.
in C code I'm stuck to pass an array of struct to a function, here's the code that resembles my problem:
typedef struct { int x; int y; char *str1; char *str2; }Struct1; void processFromStruct1(Struct1 *content[]); int main() { Struct1 mydata[]= { {1,1,"black","cat"}, {4,5,"red","bird"}, {6,7,"brown","fox"}, }; processFromStruct1(mydata);//how?!?? can't find correct syntax return 0; } void processFromStruct1(Struct1 *content[]) { printf("%s", content[1]->str1);// if I want to print 'red', is this right? ... }
Compile error in msvc is something like this:
error C2664: 'processFromStruct1' : cannot convert parameter 1 from 'Struct1 [3]' to 'Struct1 *[]' 1> Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
How to solve this? tnx.
解决方案
You almost had it, either this
void processFromStruct1(Struct1 *content);
or this
void processFromStruct1(Struct1 content[]);
and, as Alok points out in comments, change this
content[1]->str1
to this
content[1].str1
Your array is an array of structures, not an array of pointers, so once you select a particular structure with [1] there is no need to further dereference it.
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