在 Python 中以秒和纳秒为单位获取 POSIX/Unix 时间? [英] Get POSIX/Unix time in seconds and nanoseconds in Python?

问题描述

自 1970-01-01 00:00:00 UTC 以来，我一直在尝试寻找一种方法，以秒和纳秒为单位在 python 中获取时间，但我找不到任何可以给我适当精度的东西.

I've been trying to find a way to get the time since 1970-01-01 00:00:00 UTC in seconds and nanoseconds in python and I cannot find anything that will give me the proper precision.

我试过使用时间模块，但精度只有微秒，所以我尝试的代码是:

I have tried using time module, but that precision is only to microseconds, so the code I tried was:

import time

print time.time()

这给了我这样的结果:

1267918039.01

但是，我需要一个看起来像这样的结果:

However, I need a result that looks like this:

1267918039.331291406

有谁知道以秒和纳秒表示 UNIX 时间的可能方法?我找不到设置正确精度或以正确格式获得结果的方法.感谢您的帮助

Does anyone know a possible way to express UNIX time in seconds and nanoseconds? I cannot find a way to set the proper precision or get a result in the correct format. Thank you for any help

推荐答案

从 Python 3.7 开始，使用 time.time_ns()

Since Python 3.7 it's easy to achieve with time.time_ns()

与 time() 类似，但以自纪元以​​来的纳秒整数形式返回时间.

Similar to time() but returns time as an integer number of nanoseconds since the epoch.

在 Python 3.7 版本中包含纳秒的所有新功能:PEP 564:添加具有纳秒分辨率的新时间函数

All new features that includes nanoseconds in Python 3.7 release: PEP 564: Add new time functions with nanosecond resolution

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