BeautifulSoup findAll() 给出了多个类? [英] BeautifulSoup findAll() given multiple classes?
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问题描述
我想从网站上抓取项目列表，并保留它们的显示顺序.这些项目组织在一个表格中，但它们可以是两个不同类别之一(以随机顺序).
有没有办法提供多个类并让 BeautifulSoup4 找到任何给定类中的所有项目?
我需要实现这段代码的功能，除了保留源代码中的项目顺序:
items = soup.findAll(True,{'class':'class1'})items += soup.findAll(True,{'class':'class2'}) 解决方案
你可以这样做
soup.findAll(True, {'class':['class1', 'class2']})示例:
<预><代码>>>>从 bs4 导入 BeautifulSoup>>>汤 = BeautifulSoup('<html><body><div class="class1"></div><div class="class2"></div><div class="class3""></div></body></html>')>>>汤.findAll(真，{类":[类1"，类2"]})[<div class="class1"></div>, <div class="class2"></div>]I would like to scrape a list of items from a website, and preserve the order that they are presented in. These items are organized in a table, but they can be one of two different classes (in random order).
Is there any way to provide multiple classes and have BeautifulSoup4 find all items which are in any of the given classes?
I need to achieve what this code does, except preserve the order of items as it was in the source code:
items = soup.findAll(True,{'class':'class1'})
items += soup.findAll(True,{'class':'class2'})
解决方案
you can do this
soup.findAll(True, {'class':['class1', 'class2']})
example:
>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('<html><body><div class="class1"></div><div class="class2"></div><div class="class3"></div></body></html>')
>>> soup.findAll(True, {"class":["class1", "class2"]})
[<div class="class1"></div>, <div class="class2"></div>]
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