BeautifulSoup 查找包含特定单词的链接 [英] BeautifulSoup to find a link that contains a specific word

问题描述

我有这个链接:

<a href="/location/santa-clara/3fce50c4f3f9793d2f503fc145585090">Santa Clara, California</a>

如何使用 BeautifulSoup 专门查找包含位置"一词的此链接?

How can I use BeautifulSoup to find specifically this link that includes the word location "location"?

推荐答案

你可以用一个简单的 "包含" CSS 选择器:

You can do it with a simple "contains" CSS selector:

soup.select("a[href*=location]")

或者，如果只需要匹配一个链接，使用select_one():

Or, if only one link needs to be matched, use select_one():

soup.select_one("a[href*=location]")

当然，还有许多其他方法 - 例如，您可以使用 find_all() 提供了 href 参数，它可以有一个 正则表达式 值或 function:

And, of course, there are many other ways - for instance, you can use find_all() providing the href argument which can have a regular expression value or a function:

import re

soup.find_all("a", href=re.compile("location"))
soup.find_all("a", href=lambda href: href and "location" in href)

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