)
Is there a way to get the n-th tag in some code or another way that does not require going through all the tables? Or should I see if I can add titles to the tables? (like <table title="things">)
如果有帮助，每个表格上方还有标题(title
There are also headers (<h4>title</h4>) above each table, if that helps.
谢谢.
编辑
当我问这个问题时，我的想法是这样的:
Here's what I was thinking when I asked the question:
我将对象解包为两个值，但还有更多.我认为这只会给我列表中的前两件事，但当然，它一直给我上面提到的错误.我不知道返回值是一个列表，并认为它是一个特殊的对象或其他东西，我的代码基于我朋友的.
I was unpacking the objects into two values, when there were many more. I thought this would just give me the first two things from the list, but of course, it kept giving me the error mentioned above. I was unaware the return value was a list and thought it was a special object or something and I was basing my code off of my friends'.
我认为这个错误意味着页面上的表格太多，无法处理所有表格，所以我想寻求一种不用我使用的方法就能做到的方法.我可能应该停止假设.
I was thinking this error meant there were too many tables on the page and that it couldn't handle all of them, so I was asking for a way to do it without the method I was using. I probably should have stopped assuming things.
现在我知道它返回一个列表，我可以在 for 循环中使用它或使用 soup.findAll('table')[someNumber] 从中获取一个值.我还了解了拆包是什么以及如何使用它.感谢所有帮助过的人.
Now I know it returns a list and I can use this in a for loop or get a value from it with soup.findAll('table')[someNumber]. I learned what unpacking was and how to use it, as well. Thanks everyone who helped.
希望这能让事情变得清晰，现在我知道我在做什么，我的问题比我提出问题时更没有意义，所以我想我只是在这里记录一下我的想法.
Hopefully that clears things up, now that I know what I'm doing my question makes less sense than it did when I asked it, so I thought I'd just put a note here on what I was thinking.
编辑 2:
这个问题现在已经很老了，但我仍然看到我从来没有真正清楚自己在做什么.
This question is now pretty old, but I still see that I was never really clear about what I was doing.
如果它对任何人有帮助，我试图解压 findAll(...) 结果，其中的数量我不知道.
If it helps anyone, I was attempting to unpack the findAll(...) results, of which the amount of them I didn't know.
useless_table, table_i_want, another_useless_table = soup.findAll("table");
由于页面中的表格数量并不总是我猜到的，并且元组中的所有值都需要解包，所以我收到了ValueError:
Since there weren't always the amount of tables I had guessed in the page, and all the values in the tuple need to be unpacked, I was receiving the ValueError:
ValueError: too many values to unpack
因此，我一直在寻找获取返回的元组中的第二个(或任何一个索引)表的方法，而不会遇到有关使用了多少表的错误.
So, I was looking for the way to grab the second (or whichever index) table in the tuple returned without running into errors about how many tables were used.
推荐答案
从调用soup.findAll('table')中获取第二个表，将其用作列表，只需对其进行索引:
To get the second table from the call soup.findAll('table'), use it as a list, just index it:
secondtable = soup.findAll('table')[1]
这篇关于Python 中的 BeautifulSoup - 获取类型的第 n 个标签的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
