SOAP 1.2 python 客户端 [英] SOAP 1.2 python client

问题描述

我正在寻找一个 python SOAP 1.2 客户端，但它似乎不存在.所有现有的客户端要么不维护，要么只与 SOAP 1.1 兼容:

I am looking for a python SOAP 1.2 client but it seems that it does not exist . All of the existing clients are either not maintainted or only compatible with SOAP 1.1:

• 泡沫
• SOAPpy
• ZSI

推荐答案

zeep 库支持 SOAP 1.1 和 1.2，只要服务的 WSDL 正确指明.

The zeep library supports both SOAP 1.1 and 1.2 as long as the service's WSDL properly indicates it.

WSF/Python 支持 SOAP 1.2.

WSF/Python is supporting SOAP 1.2.

WSF/Python 是 WSO2 WSF/C 的 Python 语言扩展[http://www.wso2.org/projects/wsf/c].此版本使您能够使用/提供 Web 服务REST 和 SOAP.

INTRODUCTION

WSF/Python is the Python language extension to WSO2 WSF/C [http://www.wso2.org/projects/wsf/c]. This version enables you to consume/provide Web Services both with REST and SOAP.

• 支持 REST
• 支持 SOAP 1.1
• 支持 SOAP 1.2

对于下载，您无需注册.只需点击最底部的提交"即可.

For downloading, you don't have to register. Just click "submit" at the very bottom.

可以在下载的存档中找到示例，例如:

Samples can be found within the downloaded archive, eg:

LOG_DIR = '/tmp/'
LOG_LEVEL = 4
WSFC_HOME = '/opt/wso2/wsf_c'
END_POINT = 'http://localhost:9090/axis2/services/echo/echoString'

if __name__ == '__main__':
    message = """
    <ns1:echoString xmlns:ns1="http://ws.apache.org/axis2/services/echo">
        <text>Hello World!</text>
    </ns1:echoString>
    """
    try:
        client = wso2.wsf.WSClient({
            'to':END_POINT,
            'WSF_LOG_DIR':LOG_DIR,
            'WSF_LOG_LEVEL':LOG_LEVEL,
            'WSFC_HOME':WSFC_HOME,
            })

        print 'Sending: ' + message

        response = client.request(message)

        if response is not None:
            print 'Respose: ' + response + '
'
        else:
            print 'Error occurred!'
    except wso2.wsf.WSFault, e:
        print 'Exception occurred:'
        print e

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