如何用sed中的另一条路径替换一条路径? [英] How to replace a path with another path in sed?

问题描述

我有一个 csh 脚本(尽管我可以更改语言，如果有任何相关性)，我必须:

I have a csh script (although I can change languages if it has any relevance) where I have to:

sed s/AAA/BBB/ file

问题是 AAA 和 BBB 是路径，因此包含/".AAA 是固定的，所以我可以说:

The problem is that AAA and BBB are paths, and so contain '/'. AAA is fixed, so I can say:

sed s/\/A\/A\A/BBB/ file

然而，BBB 是基于变量的，包括 $PWD.如何转义 $PWD 中的/"?

However, BBB is based on variables, including $PWD. How do I escape the '/' in $PWD?

或者我应该通过其他方式完全做到这一点吗?

OR is there some other way I should be doing this entirely?

推荐答案

sed 可以在 s 命令中使用任何分隔符代替 /.只需使用您的路径中未遇到的内容:

sed can use any separator instead of / in the s command. Just use something that is not encountered in your paths:

s+AAA+BBB+

等等.

或者(如果您不想猜测)，您可以使用 sed 预处理您的路径以逃避斜线:

Alternatively (and if you don't want to guess), you can pre-process your path with sed to escape the slashes:

pwdesc=$(echo $PWD | sed 's_/_\/_g')

然后使用 $pwdesc 执行您需要的操作.

and then do what you need with $pwdesc.

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