用另一个文件的内容替换文件中的分隔文本块 [英] Replace delimited block of text in file with the contents of another file

问题描述

我需要编写一个简单的脚本，用另一个文件的内容替换配置文件中的一段文本.

I need to write a simple script to replace a block of text in a configuration file with the contents of another file.

假设有以下简化文件:

server.xml

<?xml version='1.0' encoding='UTF-8'?>
<Server port="8005" shutdown="SHUTDOWN">
  <Service name="Catalina">
    <Connector port="80" protocol="HTTP/1.1"/>
    <Engine name="Catalina" defaultHost="localhost">
      <!-- BEGIN realm -->
        <sometags/>
        <sometags/>
      <!-- END realm -->
      <Host name="localhost" appBase="webapps"/>
    </Engine>
  </Service>
</Server>

realm.xml

<Realm className="org.apache.catalina.realm.UserDatabaseRealm"
       resourceName="UserDatabase"/>

我想运行一个脚本并让 realm.xml 替换 <!-- BEGIN realm --> 和 < 之间的内容.!-- END 领域 --> 行.如果 realm.xml 发生变化，那么每当脚本再次运行时，它将再次用 realm.xml 的新内容替换这些行.这旨在在域将不同的多个安装上启动服务时在 /etc/init.d/tomcat 中运行.

I want to run a script and have realm.xml replace the contents between the <!-- BEGIN realm --> and <!-- END realm --> lines. If realm.xml changes then whenever the script is run again it will replace the lines again with the new contents of realm.xml. This is intended to be run in /etc/init.d/tomcat on startup of the service on multiple installations on which the realm is going to be different.

我不太确定如何简单地使用 awk 或 sed 来做到这一点.

I'm not so sure how can I do this simply with awk or sed.

推荐答案

试试这个:

sed -i -ne '/<!-- BEGIN realm -->/ {p; r realm.xml' -e ':a; n; /<!-- END realm -->/ {p; b}; ba}; p' server.xml

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