为什么反射不在结构中设置属性? [英] Why doesn't reflection set a property in a Struct?

查看:23
本文介绍了为什么反射不在结构中设置属性?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

   class PriceClass {

        private int value;
        public int Value
        {
            get { return this.value; }
            set { this.value = value; }
        }           
    }


    struct PriceStruct
    {

        private int value;
        public int Value
        {
            get { return this.value; }
            set { this.value = value; }
        }
    }
    static void Main(string[] args)
    {
        PriceClass _priceClass = new PriceClass();
        Type type = typeof(PriceClass);
        PropertyInfo info = type.GetProperty("Value");
        info.SetValue(_priceClass, 32, null);
        Console.WriteLine(_priceClass.Value);

        PriceStruct _priceStruct = new PriceStruct();
        type = typeof(PriceStruct);
        info = type.GetProperty("Value");
        info.SetValue(_priceStruct, 32, null);
        Console.WriteLine(_priceStruct.Value);

        Debugger.Break();
    }

打印的第一个值是 32,第二个是 0.没有抛出异常

The first value printed is 32 while the second is 0. No exception thrown

推荐答案

这是因为装箱您的结构会复制它,所以您应该更早地装箱它,以便从您修改的相同数据调用 getter.以下代码有效:

It's because boxing your struct makes a copy of it, so you should box it earlier so you call the getter from the same data that you modified. The following code works:

    object _priceStruct = new PriceStruct(); //Box first
    type = typeof(PriceStruct);
    info = type.GetProperty("Value");
    info.SetValue(_priceStruct, 32, null);
    Console.WriteLine(((PriceStruct)_priceStruct).Value); //now unbox and get value

    Debugger.Break();

这篇关于为什么反射不在结构中设置属性?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆